Answer:
72
Step-by-step explanation:
1 then 7+1=8 8+7=15 15+8=23 23+15=38 38+23=61
Ta Da I have taught you the pattern now you can show your work just in case you have one of those teachers hope this helped
Answer:
The volume of a prism is calculated by - Multiplying the area of the base by the height.
My answer might not be correct, but at least I tried
Step-by-step explanation:
Answer:
4(30 +7) = 120 +28 = 148
Step-by-step explanation:
When applying the distributive property to integers, we usually break them apart according to place value. That is not the only way it can be done.
4×37 = 4(30 +7) = 4·30 +4·7 = 120 +28 = 148
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You can also break apart 37 other ways:
4×37 = 4(35 +2) = 4·35 +4·2 = 140 +8 = 148
4×37 = 4(40 -3) = 4·40 -4·3 = 160 -12 = 148
Or, you can break apart 4:
37×4 = 37(2 +2) = 37·2 +37·2 = 74 +74 = 148
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The distributive property is usually written in generic form as ...
a(b+c) = ab +ac
Then you may want to stop after the first couple of steps:
4(30 +7) = 4·30 +4·7
We can't tell if you're suppose to evaluate the expression or not. Check your reference materials for an example of this kind of problem.
1) Our marbles will be blue, red, and green. You need two fractions that can be multiplied together to make 1/6. There are two sets of numbers that can be multiplied to make 6: 1 and 6, and 2 and 3. If you give the marbles a 1/1 chance of being picked, then there's no way that a 1/6 chance can be present So we need to use a 1/3 and a 1/2 chance. 2 isn't a factor of 6, but 3 is. So we need the 1/3 chance to become apparent first. Therefore, 3 of the marbles will need to be one colour, to make a 1/3 chance of picking them out of the 9. So let's say 3 of the marbles are green. So now you have 8 marbles left, and you need a 1/2 chance of picking another colour. 8/2 = 4, so 4 of the marbles must be another colour, to make a 1/2 chance of picking them. So let's say 4 of the marbles are blue. We know 3 are green and 4 are blue, 3 + 4 is 7, so the last 2 must be red.
The problem could look like this:
A bag contains 4 blue marbles, 2 red marbles, and 3 green marbles. What are the chances she will pick 1 blue and 1 green marble?
You should note that picking the blue first, then the green, will make no difference to the overall probability, it's still 1/6. Don't worry, I checked
2) a - 2% as a probability is 2/100, or 1/50. The chance of two pudding cups, as the two aren't related, both being defective in the same packet are therefore 1/50 * 1/50, or 1/2500.
b - 1,000,000/2500 = 400
400 packages are defective each year
