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3 years ago

6

Just need someone to explain how I simplified it to -2a+15b/ 4

2 answers:

nikitadnepr [17]3 years ago

6 0

Answer:

Step-by-step explanation:

3(4a + 6b) = 3*4a + 3*6b = 12a + 18b

-2(7a + b) = -2*7a + (-2)*b = -14a - 2b

$\frac{5[3(4a+6b)-2(7a+b)-b]}{20}=\frac{5[12a+18b-14a-2b-b]}{20}\\\\ \frac{5[-2a+15b]}{20}=\frac{15b-2a}{4}$

x =1/4

Shtirlitz [24]3 years ago

4 0

X = 1/4 ?

since multiplying fractions is straight across,

1/4 * (15b -2a) would result in the simplification you got.

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The number of green marbles is $n_g = 3$

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$P(r') = \frac{n_k}{n_t}$

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The probability of the second ball not being red is mathematically represented as

$P(r'') = \frac{n_k - 1}{n_t -1}$

=> $P(r'') = \frac{ 8 -1 }{15-1}$ (the subtraction is because the marbles where selected without replacement )

=> $P(r'') = \frac{ 7 }{14}$

The probability that the first two balls is not red is mathematically represented as

$P(R) = P(r') * P(r'')$

=> $P(R) = \frac{ 8}{15} * \frac{ 7 }{14}$

=> $P(R) = \frac{ 8 }{30}$

The probability of the third ball being red is mathematically represented as

$P(r) = \frac{n_r}{ n_t -2}$ (the subtraction is because the marbles where selected without replacement )

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=> $P(r) = \frac{7}{ 13}$

Generally the probability of the first two marble not being red and the third marble being red is mathematically represented as

$P(K) = P(R) * P(r)$

$P(K) = \frac{ 8 }{30} * \frac{7}{ 13}$

=> $P(K) = \frac{ 28 }{195}$

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