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Murrr4er [49]
3 years ago
6

Just need someone to explain how I simplified it to -2a+15b/ 4

Mathematics
2 answers:
nikitadnepr [17]3 years ago
6 0

Answer:

Step-by-step explanation:

3(4a + 6b) = 3*4a + 3*6b = 12a + 18b

-2(7a + b) = -2*7a + (-2)*b = -14a - 2b

\frac{5[3(4a+6b)-2(7a+b)-b]}{20}=\frac{5[12a+18b-14a-2b-b]}{20}\\\\ \frac{5[-2a+15b]}{20}=\frac{15b-2a}{4}

x =1/4

Shtirlitz [24]3 years ago
4 0

X = 1/4 ?

since multiplying fractions is straight across,

1/4 * (15b -2a) would result in the simplification you got.

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From the question we are told that

   The number of green marbles is  n_g  =  3

    The number of red marbles is  n_b  =  5

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Generally the total number of marbles is mathematically represented as

       n_t  =  n_r  +  n_g + n_ b

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The probability of the first ball not being red is mathematically represented as  

      P(r') =  \frac{n_k}{n_t}

=>  P(r') =  \frac{ 8}{15}

The probability of the second ball not being red is mathematically represented as

      P(r'') =  \frac{n_k - 1}{n_t -1}

=>  P(r'') =  \frac{ 8 -1 }{15-1} (the subtraction is because the marbles where selected without replacement  )

=>  P(r'') =  \frac{ 7 }{14}

The probability that the first two balls  is  not red is mathematically represented as

    P(R) =  P(r') *  P(r'')

=>  P(R) =  \frac{ 8}{15} *   \frac{ 7 }{14}

=>  P(R) =  \frac{ 8 }{30}

The probability of the third ball being red is mathematically represented as

   P(r) =  \frac{n_r}{ n_t -2} (the subtraction is because the marbles where selected without replacement  )

     P(r) =  \frac{7}{ 15 -2}

=>    P(r) =  \frac{7}{ 13}

Generally the probability of the first two marble not being red and the third marble being red is mathematically represented as

        P(K)  =  P(R) * P(r)

         P(K)  =   \frac{ 8 }{30} * \frac{7}{ 13}

=>      P(K)  =   \frac{ 28 }{195}

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