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HACTEHA [7]
3 years ago
11

A corporate team-building event costs $13, plus an additional $6 per attendee. How many

Mathematics
1 answer:
andrew-mc [135]3 years ago
5 0

Answer:

 12

Step-by-step explanation:

The cost for n attendees will be ...

 cost = 2 + 2n

We want the cost to be, at most, 26, so we have ...

 26 ≥ 2 +2n

Dividing by 2 gives ...

 13 ≥ 1 + n

And subtracting 1, we find the answer:

 12 ≥ n

At most, there can be 12 attendees.

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erica [24]
(36 3/4" + 36 3/8" + 371/2" +z) /4 = 36 5/8" 
This is the equation that you would get for the average. Now we just solve for z. 
Following PEMDAS you have to mulitply the equation by 4 to get rid of the divide by 4 part. 
4( (36 3/4" + 36 3/8" + 371/2" +z) /4 = 36 5/8)
Which does this
 36 3/4" + 36 3/8" + 371/2" +z = 146 1/2" 
Now you have to add and subtract to get "z" by itself. 
36 3/4" + 36 3/8" + 371/2" = 110 5/8" 
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3 years ago
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mr Goodwill [35]
The top row contains the product of x^{2} with each term of the expressions x^{6}+ x^{4}+ x^{2} and bottom row contains the product of -1 with each term of expression x^{6}+ x^{4}+ x^{2} .

The final result will be the sum of terms of both rows as shown below:

( x^{6}+ x^{4} + x^{2} )( x^{2} -1) \\  \\ 
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So the correct answer is option D
8 0
3 years ago
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Step-by-step explanation:

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2 years ago
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2 years ago
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