Use the following information to solve the problem using a Punnett square: Assume that the dominant "A" allele encodes normal pi
gmentation and the recessive "a" allele encodes albinism. An individual with the genotype aa has children with an individual of the genotype Aa. What is the percent chance that they would have children with albinism
1 answer:
Answer:
50% or 1/2
Explanation:
<em> chance that they would have children with albinism is 50.</em>
A allele encodes normal pigmentation.
a allele encodes albinism.
An aa individual has children with an Aa individual
aa x Aa
Offspring = Aa, aa, Aa, and aa = 2 Aa + 2 aa (See the attached Punnet's square)
Based on the assumption that the A allele is dominant over the a allele, Aa individuals will have normal pigmentation while aa individuals will be albinos.
Hence,
<em>Percentage of their children that will have normal pigmentation </em><em>(Aa</em><em>) = 50% or 1/2.</em>
<em>Percentage of their children that will be albino (</em><em>aa</em><em>)= 50% or 1/2.</em>
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