If it’s true or false then your answer is true.
I think answer is states 3
Answer:
SinA = √5/3
CosB = √5/3
Step-by-step explanation:
First let us find the value of a. This is illustrated below:
a^2 = 6^2 — 4^2
a^2 = 36 — 16
a^2 = 20
Take the square root of both side
a = √20 = √(4 x 5) = √4 x √5
a = 2√5
From the diagram,
For sinA
Opp = 2√5
Hypo = 6
Adj = 4
SinA = opp /Hypo
SinA = 2√5/6
SinA = √5/3
For CosB
Opp = 4
Hypo = 6
Adj = 2√5
CosB = Adj /Hypo
CosB = 2√5/6
CosB = √5/3
Answer:
Option 1.
The solution set is: {n|n is a real number, n≥3}
Step-by-step explanation:
1. You must read carefully the information given in the problem: "One less than twice a number" indicates that you must write a number 
multiplied by 2 and subtract 1 from this term, as following:
2. "is not less than five" indicates that the result must be equal or greater than 5. Then, you obtain the following expression:
3. Now, you can solve for . Then, you obtain:
4. Then, the solution set is: {n|n is a real number, n≥3}.
5. The correct plot on the number line must show a circle on 3 (You must fill in the circle if the sign is 
or
) with a line from that circle to the right.
5. Therefore, the answer is the first option.
The crucial part of the wording of the problem tells us that the two integers are consecutive. So, let's call the first term x. Then the other term must be x + 1 since it comes right after it and is an integer. Now we can solve:
x(x + 1) = x + (x + 1) + 19
x^2 + x = 2x + 20
x^2 - x - 20 = 0
Now we factor:
(x - 5)(x + 4) = 0
This means x either equals 5 or x = -4 to satisfy the above equation. We know that x is positive from the question itself, so x must be 5. The number consecutively after it then must be 6.
