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HACTEHA [7]
3 years ago
8

If f'(x) = cos(3^x), then the smallest value of x for which f has a relative maximum is:

Mathematics
1 answer:
anastassius [24]3 years ago
8 0

Answer:

A 0.411

Step-by-step explanation:

A graph of f'(x) is negative-going at its first zero-crossing of about x=0.411. Thus, this point where the derivative is zero corresponds to a local maximum.

_____

There are no zero crossings for negative values of x. The curve asymptotically approaches y=1.

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5 0
2 years ago
How to solve this problem
Arisa [49]
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9+ \sqrt{-4}

Knowing that the square root of a negative number doesn't exist:

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Hope it helped,

Happy homework/ study/ exam!


4 0
3 years ago
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Fofino [41]
(5b)(-3a)
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3 years ago
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Rama09 [41]

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3 years ago
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I'm stuck on this problem also
mash [69]
<span>The perimeter is 14.47
 
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3 years ago
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