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3 years ago

What is the range of the function shown in the graph below?

Mathematics

1 answer:

alexandr1967 [171]3 years ago

4 0

Answer:

y= -3/2X + 2

Step-by-step explanation:

we get the gradient by picking any two points from the graph( it a linear graph)

using the point:

(x,y)= (-2,5) , (4,-4)

using M= (y2-y1)/x2-x1)

we get our gradient to be -9/6 which is

-3/2

using the equation of a straight line graph which is

y-y1=m(x-x1) and the point (4,-4)

we get

y-(-4)=-3/2(x-4)

----> y+4= -3/2x + 6

make y subject of the formula to take the form

y=mx+c

we get :

y=-3/2x + 2

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3 years ago

how do i find the volume of a triangular prism that has a 10m width a 4m base and a 8m hight don't worry about the T

Alecsey [184]

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3 years ago

Y=x-4 and -4x-6y=-16

denis-greek [22]

Answer:

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Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Miriam is picking out some movies to rent, and she is primarily interested in comedies and foreign films. She has narrowed down

Keith_Richards [23]

Answer:

There are 795 combinations.

Step-by-step explanation:

The number of ways or combinations in which we can select k element from a group of n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, if Miriam want to choose 3 movies with at least two comedies, she have two options: Choose 2 comedies and 1 foreign film or choose 3 comedies.

Then, the number of combinations for every case are:

1. Choose 2 Comedies from the 10 and choose 1 foreign film from 15. This is calculated as:

$10C2*15C1=\frac{10!}{2!(10-8)!}*\frac{15}{1!(15-14)!}$

$10C2*15C1=675$

2. Choose 3 Comedies from the 10. This is calculated as:

$10C3=\frac{10!}{3!(10-3)!}=120$

Therefore, there are 795 combinations and it is calculated as:

675 + 120 = 795

8 0

3 years ago

If you randomly choose two letters from the word "JANUARY ", find the probability that you choose letter J first and then A afte

miss Akunina [59]

Answer:

2.0%

Step-by-step explanation:

The probability of two events happening in the sequence is calculated by multiplying the probability of each event happening separately by one another. Since there are a total of 7 letters in this word then the probability of choosing one letter correctly is $\frac{1}{7}$ . Since the first letter is replaced before choosing the second letter the probability remains the same. Therefore, the sequence would be the following...

$\frac{1}{7} * \frac{1}{7}$ = 0.020164 or 2.0%

This is an independent scenario because it does not depend on any external factors and under these circumstances the percentage will remain the same.

3 0

3 years ago