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3 years ago

Please help fast!!!

Mathematics

2 answers:

blondinia [14]3 years ago

7 0

Answer:

Step-by-step explanation:

because i said so and its right

denpristay [2]3 years ago

6 0

Answer:

whats the question

Step-by-step explanation:

ask the question

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All I need to know is how to do 13. After I know how to do 13, I'll know how to do the rest. Please show your work and explain i

s2008m [1.1K]

MK is the same as NL.
Just read the rest of the questions.
They practically give you the answers.

7 0

3 years ago

If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.

Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴ m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

4 0

1 year ago

What is .50 as a benchmark fraction

Alinara [238K]

Answer: 1/2

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Edward's cake recipe calls for 15 3/4 cups of flour and

rodikova [14]

Cups of flour=15 3/4=15+ 3/4=(4*15+3)/4=63/4
Cups of sugar=10 1/2=(2*10+1)/2=21/2

We solve this problem by rule of 3:

63/4 cups of flour--------------100 people
x------------------------------------ 25 people

x=(63/4 cups of flout * 25 people)/100 people=1575/400 cups of flour=
=63/16=(3*16+15)/16=3 15/16 cups of flour.

21/2 cups of sugar-----------------100 people
x-----------------------------------------25 people

x=(21/2 cups fo sugar * 25 people) / 100 people=525/200 cups of sugar= 21/8 =(2*8+ 5)/8=2 5/8 cups of sugar.

Answer: 3 15/16 cups of flour and 2 5/8 cups of sugar.

8 0

3 years ago

From a piece of tin in the shape of a square 6 inches on a side, the largest possible circle is cut out. What is the ratio of th

wel

Answer:

$\sf \dfrac{1}{4} \pi \quad or \quad \dfrac{7}{9}$

Step-by-step explanation:

The width of a square is its side length.

The width of a circle is its diameter.

Therefore, the largest possible circle that can be cut out from a square is a circle whose diameter is equal in length to the side length of the square.

Formulas

$\sf \textsf{Area of a square}=s^2 \quad \textsf{(where s is the side length)}$

$\sf \textsf{Area of a circle}=\pi r^2 \quad \textsf{(where r is the radius)}$

$\sf \textsf{Radius of a circle}=\dfrac{1}{2}d \quad \textsf{(where d is the diameter)}$

If the diameter is equal to the side length of the square, then:
$\implies \sf r=\dfrac{1}{2}s$

Therefore:

$\begin{aligned}\implies \sf Area\:of\:circle & = \sf \pi \left(\dfrac{s}{2}\right)^2\\& = \sf \pi \left(\dfrac{s^2}{4}\right)\\& = \sf \dfrac{1}{4}\pi s^2 \end{aligned}$