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2 years ago

7

The price of a visit to the dentist is \$50$50. If the dentist fills any cavities, an additional charge of \$100$100 per cavity

gets added to the bill. If the dentist finds nn cavities, what will the cost of the visit be?

1 answer:

kenny6666 [7]2 years ago

7 0

Answer:300

Step-by-step explanation:

um i dk know if the two 50$ means any thing but thats what i got

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A fishing store gives customers 10 new lures for every 2 fishing poles they buy. How

Firlakuza [10]

Answer:

40 lures

Step-by-step explanation

First, 10 for every 2 means multiplication. 2 goes into 8 4 times. 4x2=8

10 lures multiplied by 4 is 40.

I hope this helps! ツ

3 0

2 years ago

AABC ~ADEF<br> F<br> 21<br> D<br> B<br> N<br> 28<br> E<br> C<br> Solve for N.<br> 28 = ☆<br> N=[?]

sergij07 [2.7K]

Answer:

N = 3

Step-by-step explanation:

$\frac{28}{4} = \frac{21}{N} \\ \\ 28N = 21 \times 4 \\ 28N = 84 \\ \\ N = \frac{84}{28} \\ \\ N = 3$

I hope I helped you^_^

8 0

2 years ago

Find the distance between each pair of points.round your awnser to the nearest tenths,if nessesary (-3,-4),(0,0) problem 2 (-8,0

Arte-miy333 [17]

Answer:

1st one: -3,-4 away

2nd one: Lets just say I got kinda confused on that one so sorry for any inconvenience on my behalf from this question.

Step-by-step explanation:

I will call (-3,-4) Point A and I'll call (0,0) Point B. Point A is at (-3,-4) and Point B is obviously at the origin. That makes it easy, because you just subtract Point A by Point B to find how far away they are.

3 0

2 years ago

A total of 585 tickets were sold for the school play. They were either adult tickets or student tickets. There were 65 fewer stu

natulia [17]

Answer:

325

Step-by-step explanation:

Total Tickets = 585

Let the adult tickets be = x

If 65 fewer student tickets were sold than adult tickets then Student tickets = x-65

Student Tickets + Adult Tickets = 585

x + (x-65) = 585

x + x - 65 = 585

2x - 65 = 585

2x = 585 + 65

2x = 650

2x/2 = 650/2

x = 325

Answered by Gauthmath

3 0

2 years ago

A human resources representative claims that the proportion of employees earning more than $50,000 is less than 40%. To test thi

bearhunter [10]

Answer:

The statistic for this case would be:

$z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}$

And replacing we got:

$z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92$

Step-by-step explanation:

For this case we have the following info:

$n =700$ represent the sample size

$X= 305$ represent the number of employees that earn more than 50000

$\hat p=\frac{305}{700}= 0.436$

We want to test the following hypothesis:

Nul hyp. $p \leq 0.4$

Alternative hyp : $p>0.4$

The statistic for this case would be:

$z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}$

And replacing we got:

$z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92$

And the p value would be given by:

$p_v = P(z>1.922)= 0.0274$

4 0

3 years ago