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Nat2105 [25]
4 years ago
14

$1334 is deposited into a savings account at 8% interest, compounded quarterly. To the nearest year, how long will it take for t

he account balance to reach $1,000,000?
Mathematics
1 answer:
Varvara68 [4.7K]4 years ago
5 0

Answer:

  84 years

Step-by-step explanation:

The future value of an investment is given by ...

  FV = P(1 +r/n)^(nt)

where P is the principal amount, r is the annual rate, and n is the number of times per year interest is compounded. Filling in the given values and solving for t, we get ...

  1000000 = 1334(1 +.08/4)^(4t)

  749.6252 ≈ 1.02^(4t) . . . . divide by 1334 and simplify

  log(749.6252) ≈ 4t·log(1.02) . . . . take logarithms

  t ≈ log(749.6252)/(4·log(1.02)) ≈ 83.57

It will take about 84 years for the account balance to reach $1,000,000.

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What is 2/5 y + 1/5 x -0.2y-6+(-2)
Sliva [168]

Answer:

\frac{y}{5} + \frac{x}{5}-8

Step-by-step explanation:

1)  Simplify 2 /5y to 2y/5.

\frac{2y}{5} + \frac{1}{5} x-0.2 y-6-2

2) simplify 1/5x to x/5.

\frac{2y}{5} +\frac{x}{5} -0.2y-6-2

3) Collect like terms.

(\frac{2y}{5} -0.2y) + \frac{x}{5} +(-6-2)

4) Simplify.

\frac{y}{5}+ \frac{x}{5} -8

<em><u>Therefor, the answer is </u></em><em><u>y/5 + x/5 -8</u></em>.

6 0
3 years ago
Divide. Write in simplest form.
butalik [34]
Yes. / = divide & * = multiply.
As for the equation, 10 divided by 1 2/3 is 15
7 0
3 years ago
Interest on $3,000 at 5 1/2 % for 6 months
disa [49]

The interest should equal $990. First, you have to convert the rate per month into years, and then use the formula Interest=principal x interest per year x time in years

7 0
3 years ago
I just need the answer no explanation
Elza [17]
The answer is the second choice
8 0
3 years ago
Please show full solutions! WIll Mark Brainliest for the best answer. <br><br> SERIOUS ANSWERS ONLY
Ierofanga [76]

Answer:

  • vertical scaling by a factor of 1/3 (compression)
  • reflection over the y-axis
  • horizontal scaling by a factor of 3 (expansion)
  • translation left 1 unit
  • translation up 3 units

Step-by-step explanation:

These are the transformations of interest:

  g(x) = k·f(x) . . . . . vertical scaling (expansion) by a factor of k

  g(x) = f(x) +k . . . . vertical translation by k units (upward)

  g(x) = f(x/k) . . . . . horizontal expansion by a factor of k. When k < 0, the function is also reflected over the y-axis

  g(x) = f(x-k) . . . . . horizontal translation to the right by k units

__

Here, we have ...

  g(x) = 1/3f(-1/3(x+1)) +3

The vertical and horizontal transformations can be applied in either order, since neither affects the other. If we work left-to-right through the expression for g(x), we can see these transformations have been applied:

  • vertical scaling by a factor of 1/3 (compression) . . . 1/3f(x)
  • reflection over the y-axis . . . 1/3f(-x)
  • horizontal scaling by a factor of 3 (expansion) . . . 1/3f(-1/3x)
  • translation left 1 unit . . . 1/3f(-1/3(x+1))
  • translation up 3 units . . . 1/3f(-1/3(x+1)) +3

_____

<em>Additional comment</em>

The "working" is a matter of matching the form of g(x) to the forms of the different transformations. It is a pattern-matching problem.

The horizontal transformations could also be described as ...

  • translation right 1/3 unit . . . f(x -1/3)
  • reflection over y and expansion by a factor of 3 . . . f(-1/3x -1/3)

The initial translation in this scenario would be reflected to a translation left 1/3 unit, then the horizontal expansion would turn that into a translation left 1 unit, as described above. Order matters.

8 0
2 years ago
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