Question

There are 5 red and 9 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probability of choosing 2 red balls and then 1 green ball?

Answer 1

Answer:

The probability of choosing 2 red balls and then 1 green ball is:

225/2744

Step-by-step explanation:

There are 5 red and 9 green balls in a bag.

Total balls=5+9=14

We randomly choose balls one at a time, with replacement.

(we draw a ball, look at it and place it in the bag and then draw another one)

P(choosing 2 red balls and then 1 green ball)

= $\dfrac{5}{14}\times \dfrac{5}{14}\times \dfrac{9}{14}$

= 225/2744

Hence, the probability of choosing 2 red balls and then 1 green ball is:

225/2744

Answer 2

If there are 5 red & 9 green balls in one bag and you randomly choose the balls one at a time. The probability of choosing 2 red balls and then 1 green ball is 225/2744.