There are 5 red and 9 green balls in a bag. If you randomly choose balls one at a time, with replacement, what is the probabilit
2 answers:
Answer:
The probability of choosing 2 red balls and then 1 green ball is:
225/2744
Step-by-step explanation:
There are 5 red and 9 green balls in a bag.
Total balls=5+9=14
We randomly choose balls one at a time, with replacement.
(we draw a ball, look at it and place it in the bag and then draw another one)
P(choosing 2 red balls and then 1 green ball)
=
= 225/2744
Hence, the probability of choosing 2 red balls and then 1 green ball is:
225/2744
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Answer:
14 and 16.
Step-by-step explanation:
We know that two consecutive even numbers is 30.
Let's let n be <em>any number</em>.
Then the first <em>even</em> number must be 2n.
This is because n can be any number, either even or odd. However, if we multiply it by 2, this <em>ensures</em> that 2n is even. Remember that any number multiplied by 2 yields an even number.
Therefore, the consecutive even number will be (2n+2). Not (2n+1), because that gives an odd number.
We know that they sum to 30. So, we can write the following equation.
And we solve from there:
So, the value of n is 7.
Therefore, the first even number is 7(2)=14.
And the consecutive even number is 16.
Edit: Typo