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Butoxors [25]
3 years ago
13

Your school wants to take out an ad in the paper congratulating the basketball team on a successful​ season, as shown to the rig

ht. The area of the photo will be half the area of the entire ad. What is the value of​ x?
Mathematics
1 answer:
iogann1982 [59]3 years ago
3 0

Answer:

x_1 =-14.43 in, x_2 = 2.426in

Since the measurement can't be negative the correct answer for this case would be x =2.426 in

Step-by-step explanation:

Let's assume that the figure attached illustrate the situation.

For this case the we know that the original area given by:

A_i = 7 in *5 in = 35in^2

And we know that the initial area is a half of the entire area in red A_i = \frac{A_f}{2}, so then:

A_f = 2 A_ i =2*35 = 70

And we know that the area for a rectangular pieces is the length multiplied by the width so we have this:

70 = (x+7) (x+5)

We multiply both terms using algebra and the distributive property and we got:

70 =x^2 +12 x +5

And we can rewrite the expression like this:

x^2 +12 x -35 = 0

And we can solve this using the quadratic formula given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

Where a = 1, b =12 and c=-35 if we replace we got:

x = \frac{-12 \pm \sqrt{(12)^2 -4(1)(-35)}}{2*1}

And the two possible solutions are then:

x_1 =-14.43 in, x_2 = 2.426in

Since the measurement can't be negative the correct answer for this case would be x =2.426 in

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