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Lera25 [3.4K]
3 years ago
9

Kim took C dollars to the sporting goods store to spend on new cleats. If the cleats cost $53.62, which of the following express

ions represents the number of dollars Kim will have after buying the cleats?
Mathematics
1 answer:
Mila [183]3 years ago
8 0
C-53.62 times however many she bought.

so c-(53.62x)

because you are taking how much money she spent and subracting it from how much she had
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Greeley [361]
F(x) = (x - 4) (x^2 + 4) would be your answer.
4 0
2 years ago
I just need all the numbers on top in feet on the graph please
sattari [20]

Answer:

2.5, 5, 7.5

Step-by-step explanation:

Count.

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2 years ago
3 Select the correct answer. How can you write the expression 7(b – 2) in words? A. two subtracted from the quotient of seven di
aniked [119]

Answer:

E. the product of seven and the difference of b minus two

Step-by-step explanation:

7(b-2)

seven is being multiplied by the difference of b minus 2

So this can be written as the product of seven and the difference of b minus two.

Reasons its not the other answer choices

A. two subtracted from the quotient of seven divided by b would be (7/b) - 2

B. seven added to difference of b minus two would be 7 + (b-2)

C. the quotient of seven divided by b minus two would be 7/(b-2)

D. two subtracted from seven times b would be 7b - 2

Key Vocabulary:

<em>Difference = Subtraction</em>

<em>Product = Multiplication</em>

<em>Quotient = Division </em>

<em></em>

4 0
2 years ago
Read 2 more answers
The width of a rectangle field is 3h yards and its length is 3 yards longer than the width. The field has a fence around its per
d1i1m1o1n [39]

Answer:

Part a) P=(12h+2)\ yd

Part b) The expression that represent the cost of fencing the field is (336h+56)

Part c) \$1,736

Step-by-step explanation:

<u>The complete question in the attached figure</u>

Part a) we know that

The perimeter of the rectangular field (excluding the width of the gate) is equal to

P=2(L+W)-4

we have

L=(3h+3)\ yd\\W=3h\ yd

substitute the given values

P=2(3h+3+3h)-4

P=2(6h+3)-4\\P=12h+6-4\\P=(12h+2)\ yd

Part b) we know that

To find out the cost of fencing the field (excluding the gate) , multiply the perimeter by the cost of $28 per yard

so

28(12h+2)=336h+56

Part c) we have

h=5

substitute the value of h in the expression of the cost

336(5)+56=\$1,736

8 0
3 years ago
I need some help with math
Irina18 [472]

Answer:

(y-7)^2+(x-2)^2=16

and

(x+2)^2+(y-15)^2 = 9

Step-by-step explanation:

The standard equation of a circle is (x-h)^2+(y-k)^2=r^2 where the coordinate (h,k) is the center of the circle.  

Second Problem:

  1. We can start with the second problem which uses this info very easily.
  2. (h,k) in this problem is (-2,15) simply plug these into the equation. (x--2)^2+(y-15)^2=r^2 .
  3. We can also add the radius 3 and square it so it becomes 9. The equation.
  4. This simplifies to (x+2)^2+(y-15)^2 = 9.

First Problem:

  1. The first problem takes a different approach it is not in standard form. But we can convert it to standard form by completing the square.
  2. y^2-14y+x^2-4x+37=0 first subtract 37 from both sides so the equation is now y^2-14y+x^2-4x=-37.
  3. y^2-14y+x^2-4x+37=0 by adding (-\frac{b}{2a} )^2 to both the x and y portions of this equation you can complete the squares. (-\frac{b}{2a})^2=(-\frac{-14}{2(1)})^2 and (-\frac{-4}{2(1)})^2 which equals 49 and 4.
  4. Add 49 and 4 to both sides and the equation is now:y^2-14y+49+x^2-4x+4=-37+49+4 You can simplify the y and x portions of the equations into the perfect squares or factored form (y-7)^2 and (x-2)^2.
  5. Finally put the whole thing together. (y-7)^2+(x-2)^2=16.

I hope this helps!

5 0
3 years ago
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