F(x) = (x - 4) (x^2 + 4) would be your answer.
Answer:
2.5, 5, 7.5
Step-by-step explanation:
Count.
Answer:
E. the product of seven and the difference of b minus two
Step-by-step explanation:
7(b-2)
seven is being multiplied by the difference of b minus 2
So this can be written as the product of seven and the difference of b minus two.
Reasons its not the other answer choices
A. two subtracted from the quotient of seven divided by b would be (7/b) - 2
B. seven added to difference of b minus two would be 7 + (b-2)
C. the quotient of seven divided by b minus two would be 7/(b-2)
D. two subtracted from seven times b would be 7b - 2
Key Vocabulary:
<em>Difference = Subtraction</em>
<em>Product = Multiplication</em>
<em>Quotient = Division </em>
<em></em>
Answer:
Part a) 
Part b) The expression that represent the cost of fencing the field is 
Part c) 
Step-by-step explanation:
<u>The complete question in the attached figure</u>
Part a) we know that
The perimeter of the rectangular field (excluding the width of the gate) is equal to

we have

substitute the given values


Part b) we know that
To find out the cost of fencing the field (excluding the gate) , multiply the perimeter by the cost of $28 per yard
so

Part c) we have
h=5
substitute the value of h in the expression of the cost

Answer:
and

Step-by-step explanation:
The standard equation of a circle is
where the coordinate (h,k) is the center of the circle.
Second Problem:
- We can start with the second problem which uses this info very easily.
- (h,k) in this problem is (-2,15) simply plug these into the equation.
. - We can also add the radius 3 and square it so it becomes 9. The equation.
- This simplifies to
.
First Problem:
- The first problem takes a different approach it is not in standard form. But we can convert it to standard form by completing the square.
first subtract 37 from both sides so the equation is now
.
by adding
to both the x and y portions of this equation you can complete the squares.
and
which equals 49 and 4.- Add 49 and 4 to both sides and the equation is now:
You can simplify the y and x portions of the equations into the perfect squares or factored form
and
. - Finally put the whole thing together.
.
I hope this helps!