Answer:
ITS NOT A LINEAR EQUATION SO IT DOES NOT HAVE A SLOPE
Step-by-step explanation:
Answer:
Antoinette's error
Option A) She distributed incorrectly.
Step-by-step explanation:
We are given the following information in the question:
Antoinette solves the linear equation
Antoinette made mistake in step 1 that is she did not distributed correctly.
If she would have distributed correctly, then she would have got the following solution:
Substituting x = -1 in the given equation, we gwt:
Antoinette's error
Option A) She distributed incorrectly.
Answer:
4
Step-by-step explanation:
Given that R(ABCDE) is in Boyce-Codd normal form.
And AB is the only key for R.
Definition
A relational nontrivial Schema R is in BCNF if FD (X-A) holds in R, Super key of R. whenever then X is
a
Given that AB is the only key for R.
ABC E (Yes).
check if ABC is a Super key. AB is a key, ABC is A B C E is in BONE a super key.
2) ACE B
(NO). no Check if ACE As there is ACE is not a Super key? AB in Super key. ACE.
ACE B
is
Boyce-Codd Normal Form not in BENE (NO)
3) ACDE → B (NO)
check if is a super key. ACDE
As ACDE there is not any AB Tn ACDE. a super key.
ACDEB is not in BCNF.
4) BS → C → (NO)
As there is no AB in BC ~. B(→ not in BCNF
BC is not a super key.
5) ABDE (Yes).
Since AB is a key.
ABO TS a super key.
.. ABDE → E is in BCNF
Let R(ABCDE) be a relation in Boyce-Codd Normal Form (BCNF). If AB is the only key for R, identify each of these FDs from the following list. Answer Yes or No and explain your answer to receive points.
1. ABC E
2. ACE B
3. ACDE B
4. BC C
5. ABD E
Learn more about Boyce-Codd Normal Form at
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(2/3)*(c-18)=7 <em>(Multiply terms on both sides of equation by 3)</em>
2(c-18)=21
2c-36=21
2c=57
c=57/2
c=28.5
