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VLD [36.1K]
3 years ago
10

It snowed 4.22 inches on Monday and 0.9 inches on Tuesday. How much did it snow Monday and Tuesday combined?

Mathematics
1 answer:
motikmotik3 years ago
5 0

Answer:

5.12 inches

Step-by-step explanation:

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Aleksandr-060686 [28]

Answer:

My answer was wrong!! The person above had the correct answer (613 feet) :)

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Find the arc length. Round the answer to two decimal places.
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372.233

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7 0
3 years ago
Sales prices of baseball cards from the 1960s are known topossess a skewed-right distribution with a mean sale price of $5.25and
Serga [27]

Answer:

c. Skewed-right with a mean of $5.25 and a standard error of$0.28

Step-by-step explanation:

As we have given that Sales prices of baseball cards have a right-skewed distribution with a mean $5.25 and a standard deviation is $2.80.

Now, We know that if standard deviation = σ

then, standard error = \frac{\sigma}{\sqrt{n}}

As, we have standard deviation = $2.80

then standard error will be \frac{2.80}{\sqrt{100}}

⇒ Standard error = $0.28

Hence, Option (c) is the correct option.

6 0
3 years ago
A manufacturer has been selling 1400 television sets a week at $450 each. A market survey indicates that for each $21 rebate off
GuDViN [60]

Correct question is;

A manufacturer has been selling 1400 television sets a week at $450 each. A market survey indicates that for each $21 rebate offered to a buyer, the number of sets sold will increase by 210 per week

A) Find the demand function (price p as a function of units sold x).

p(x)=______

(B) How large a rebate should the company offer the buyer in order to maximize its revenue?

$=_____

Answer:

A) p(x) = (-1/10)x + 590

B) Rebate = $170

Step-by-step explanation:

A) We are told that p(x) is the demand function and x is the number of TV sets sold per week.

Now, since for each $21 rebate offered, the number of sets sold increases by 210 per week, it means that the slope here of this demand function is; m = -21/210 = -1/10

Now, he has been selling 1400 TV sets a week at $450 each. This means; p(1400) = $450

Thus, the demand function will be;

p(x) - 450 = (-1/10)(x - 1400)

Expanding the RHS;

p(x) - 450 = (-1/10)x + 140

Add 450 to both sides to get;

p(x) = (-1/10)x + 140 + 450

p(x) = (-1/10)x + 590

B) Formula for revenue is;

R = price × quantity sold

Our demand function is p = (-1/10)x + 590

Making x the subject, we have;

x = 5900 - 10p

x is quantity sold.

Thus,

R = p(5900 - 10p)

R = 5900p - 10p²

Maximum price will occur at dR/dP = 0

Thus;

dR/dP = 5900 - 20p

At dR/dP = 0,we have;

20p = 5900

p = 5900/20

p = $280

Thus, rebate = 450 - 280 = $170

6 0
2 years ago
The table shows values for functions f(x) and g(x) .
sladkih [1.3K]
The first thing we must do for this case is to equal both functions and clear the value of x. Thus, we obtain the values that satisfy both equations.
 However, there is another solution route. We have a table with the values.
 The solution for f (x) = g (x) will be all x satisfying both equations simultaneously.
 f (0) = g (0) = 1
 f (1) = g (1) = 1/2
 answer
 x = 0
 x = 1
 Note:
 F (0) in the table is incorrect if the function is
 f (x) = 0.5x
 F (0) in the table is correct if the function is
 f (x) = 0.5 ^ x
5 0
3 years ago
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