Answer:
This exercise is incomplete, missing the value of k (decay constant), which is equal to 4x10⁻⁸s⁻¹ at 25°C
The answer is 0.549 years
Explanation:
Given:
first order of reaction
k = 4x10⁻⁸s⁻¹
For a first order of reaction, the half-life time for the degradation of DDT is equal to:
Answer:
If this is supposed to be an essay, do some reaseach...
Explanation:
De answer is A!!!!!!!!!!!!!!!!!!!!!!!!!!!!
hope it helps!!!!!!!!!!!!!!!!!
a is right!!!!!!!!!!!!!
Answer:
Optimum pH= 6
Optimum pH for the given enzyme would be the average of pKa values of two amino acids (2.9 + 9.1 /2= 6)
Explanation:
The pKa represents the association constant of amino acids. It is calculated by taking the negative log value of the ratio of a dissociated acid and the conjugated base which in turn regulates the isoelectric point (pI) of the protein.
The amino acids present in the active site of the enzyme regulate the interaction of enzyme and substrate. The given enzyme contains two ionizable amino acids with pKa values of 2.9 and 9.1 respectively. Therefore, the optimum pH of the given enzyme would be 2.9 + 9.1 / 2 = 12/2 = 6.
At pH 6, both the ionizable amino acids would serve as a good buffer with their active proton donor and proton acceptor species.
In diseases, similar patterns of mutations in harmless genes may possibly be a cause or an effect of the disease. To investigate if it is a cause, it is worth looking into the proteins synthesized by the gene and whether it’s structure or functionality is affected by the pattern observed. It is also worth looking into the downstream effects possibly caused by the pattern in the gene. The gene may encode a non coding region which could affect post transcriptional splicing for example.
