Answer:
C. both student 1 and student 2
Step-by-step explanation:
Dilation does not change any angles, so the triangles are similar and the trig functions of corresponding angles will be identical.
The slope of CB is -1/3 and the slope of BA is 3, so they multiply together to give -1. That means the segments are at right angles and the triangle is a right triangle.
Both the premise and the conclusion of each student is correct.
This is an arithmetic series, so we know, that:
Sum = (First term + Last term) * Number of terms /2
Here we have:
First term = 33
Last term = 104
Number of terms = 104 - 33 + 1 = 72
and
Answer:9
Step-by-step explanation: square root of 25 is 5 and of 16 the square root is 4 add both of them together and you get 9
We are given expression: ![(2x^4y^5)^{3/8}](https://tex.z-dn.net/?f=%282x%5E4y%5E5%29%5E%7B3%2F8%7D)
Let us distribute 3/8 over exponents in parenthesis, we get
![(2^{3/8}x^{4\times 3/8}y^{5\times 3/8}) = (2^{3/8}x^{12/8}y^{15/8})](https://tex.z-dn.net/?f=%282%5E%7B3%2F8%7Dx%5E%7B4%5Ctimes%203%2F8%7Dy%5E%7B5%5Ctimes%203%2F8%7D%29%20%3D%20%282%5E%7B3%2F8%7Dx%5E%7B12%2F8%7Dy%5E%7B15%2F8%7D%29)
![= (2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} )](https://tex.z-dn.net/?f=%3D%20%282%5E%7B3%2F8%7Dx%5E%7B1%5Cfrac%7B4%7D%7B8%7D%7D%20y%5E%7B1%5Cfrac%7B7%7D%7B8%7D%7D%20%29)
We can get x and y out of the radical because, we get whlole number 1 for x and y exponents for the mixed fractions.
So, we could write it as.
![(2^{3/8}x^{1\frac{4}{8}} y^{1\frac{7}{8}} ) = xy(2^{\frac{3}{8} }x^{\frac{4}{8}} y^{\frac{7}{8}} )](https://tex.z-dn.net/?f=%282%5E%7B3%2F8%7Dx%5E%7B1%5Cfrac%7B4%7D%7B8%7D%7D%20y%5E%7B1%5Cfrac%7B7%7D%7B8%7D%7D%20%29%20%3D%20xy%282%5E%7B%5Cfrac%7B3%7D%7B8%7D%20%7Dx%5E%7B%5Cfrac%7B4%7D%7B8%7D%7D%20y%5E%7B%5Cfrac%7B7%7D%7B8%7D%7D%20%29)
Now, we could write inside expression of parenthesis in radical form.
![xy\sqrt[8]{2x^{3}x^4y^7}](https://tex.z-dn.net/?f=xy%5Csqrt%5B8%5D%7B2x%5E%7B3%7Dx%5E4y%5E7%7D)