Answer: Option B and option D.
Step-by-step explanation:
We know that a quadrilateral is a 2-dimensional closed shape that has four sides.
By definition the diagonals of a quadrilateral are the lines that connect two non-adjacent vertices.
The following quadrilaterals have diagonals that are perpendicular to each other (also known as perpendicular bisector diagonals), which means that they form four angles of 90 degrees (right angles): <em>Rhombus and Square.</em>
Therefore the answers are: the option B and the option D.
<span>f(x) = -6x +6
to find inverse
x = -6y + 6
6y = 6 - x
y = 1 - x/6
Answer
</span>f^–1(x)= 1 - x/6
Answer:-8x^2-6x+36xy^2+27y^2
Step-by-step explanation:
using the FOIL method
Answer:
Graph 1: Consistent Dependent
Graph 2: Consistent Independent
Graph 3: Consistent Dependent
Graph 4: Inconsistent
Step-by-step explanation:
Consistent means they have at least one solution. So lines that intersect once or lines that intersect infinitely many times are both consistent systems.
If they are the system that has one solution they are considered independent.
If they are the system that has infinitely many solutions then are considered dependent.
Inconsistent means they won't intersect at all.
First graph shows the same line graphed onto itself. That means they have infinitely many solutions and is therefore a consistent dependent system.
Second graph shows the lines intersecting once. That means they have one solution and therefore is a consistent independent system.
Third graph shows the same description of graph one and is therefore a consistent dependent system.
The last graph shows parallel lines. Parallel lines do not intersect and therefore do not have a solution. So this system is inconsistent.
Usando el teorema de altura El teorema de altura relaciona la altura (h) de un triángulo rectángulo (ver figura) y los catetos de dos triángulos que son semejantes al anterior ABC, al trazar la altura (h) sobre la hipotenusa. De manera que e<span>n todo </span>triángulo rectángulo, la altura (h<span>) relativa a la </span>hipotenusa<span> es la </span>media geométrica<span> de las dos proyecciones de los </span>catetos<span> sobre la </span>hipotenusa<span> (</span>n<span> y </span>m<span>). Es decir, se cumple que:
</span>

Dado que el problema establece <span>construir un segmento cuya longitud sea media proporcional entre dos segmentos de 4 y 9 cm, entonces, digamos que n = 4cm y m = 9cm tenmos que:
</span>

De donde:
¿Cómo se podria construir si los segmentos son de a cm y b cm?
Si los segmentos son de a y b cm entonces a y b son parámetros que pueden tomar cualquier valor positivo siempre que se cumpla que:
