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3 years ago

Mark's brother is 5 years older than Mark. Their combined ages add up to 23. How old is Mark?

Mathematics

2 answers:

Mariana [72]3 years ago

4 0

Answer:

Mark is 9.

9+5 =14

14+9=23

anygoal [31]3 years ago

3 0

Answer:

Mark would be 9

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Find g(x), where g(x) is the translation 7 units up of f(x)=x2.

AfilCa [17]

Answer:

$g(x)=x^2+7$

$g(x)$ in the form $a(x-h)^2+k$ would be:

$g(x)=(x-0)^2+7$

Step-by-step explanation:

Given:

Parent function:

$f(x)=x^2$

Translation occurs 7 units up to get $g(x)$

Translation Rules:

$f(x)\rightarrow f(x)+c$

If $c>0$ the function shifts $c$ units to the up.

If $c$ the function shifts $c$ units to the down.

So, from the above rules $g(x)$ can be represented as:

$g(x)=f(x)+7$ [7 units up]

$g(x)=x^2+7$

Writing $g(x)$ in the form $a(x-h)^2+k$ where $a, h, and\ k$ are integers.

$g(x)=1(x-0)^2+7$

$g(x)=(x-0)^2+7$

3 0

3 years ago

Read 2 more answers

The area of a circle A is 85π ft2. ∠BAC is a central angle of the circle, and m∠BAC = 36°

BlackZzzverrR [31]

As stated the area of the circle is 85π ft2. The area of the sector BAC is a portion of this full circle area. the sector is made of 2 radii and arc that has rotated by 36°.
the magnitude of the central angle in the circle is 360°
Area for 360° central angle -  85π ft2
then the area for 1° =  85π ft2/360°
the area of 36° sector =  85π ft2/360° x 36°
=  8.5π ft2

7 0

3 years ago

Diane has $334 in her checking account. She writes a check for $112, makes a deposit of $100, and then writes another check for

Dmitrij [34]

Answer:

334 - 112 + 100 - 98

Step-by-step explanation:

5 0

2 years ago

Mary sold 147 bags of popcorn in 3 days. At this rate, how many bags of popcorn will Mary sell in 5 1/2 days?

lord [1]

Answer:

147bags=3days

?bags=5 1/2days

147×11/2

1617÷3

1617×1

2 3

=539/2

=269 1/2 bags or 269.5bags

5 0

2 years ago

Which of the following is an extraneous solution of (45-3x)^1/2=x-9?

Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

$\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6$

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0

3 years ago