Pleaseee help <br> I’m failing I just need one more answer

I don’t understand it’s really confusing. This was due an hour ago please help I’m struggling!

Mars2501 [29]

Step-by-step explanation:

What you are dealing with is what we call special right triangles. There are two types of right triangles.

30-60-90 triangle- A special

right triangle with side length ratio as

$(a)(a \sqrt{3} )(2a)$

, where a is any positve number

45-45-90- a special right triangle which side length ratios are

$(a)(a)(a \sqrt{2)}$

where a is any positve number.

45 45 90 triangles is indicated by two congruent side measures( if the legs are congruent and it has a right angle, it is a 45-45-90.

30-60-90 triangles is indicated by a having at least two of the following angles given (30,60, and 90).

Shortcuts:

For a 45 45 triangle,

the legs are equal while the hypotenuse is the sqr root of 2 times than the legs.

Example, look at 1. The legs side length is 12 so our hypotenuse side length will be

$12 \sqrt{2}$

For a 30-60-90 triangle, the side that is adjacent to the 30 and 90 degree measure sqr root of 3 times more than the horizontal leg.

the slanted side or the side which is adjacent to the 30 and 60 degree angle is twice the length of the horizontal leg or the side that is adjacent to the 60 and 90 degree.

Example, look at 3. We need to find x but we are given the horizontal side so just multiply sqr root of 3 to 12.

$x = 12 \sqrt{3}$

$1.12 \sqrt{2}$

2.Both equal

$2.8 \sqrt{2}$

$3.12 \sqrt{3}$

4. a=13

$4.13 \sqrt{3}$

$5.9 \sqrt{4}$

6 0

3 years ago

Solve the proportion for x. 2/9=3/(x+2)

attashe74 [19]

Answer:

x as a fraction: 11 $\frac{1}{2}$

Step-by-step explanation:

Variable x cannot be equal to −2 since division by zero is not defined. Multiply both sides of the equation by 9(x+2), the least common multiple of 9,x+2.

2 ( x+ 2) = 9 x 3

Use the distributive property to multiply 2 by x + 2.

2x + 4 = 9 x 3

Multiply 9 and 3 to get 27.

2x + 4 = 27

Subtract 4 from both sides.

2x = 27 - 4

Subtract 4 from 27 to get 23.

2x = 23

Divide both sides by 2.

x = $\frac{23}{2}$

Simplify

11 $\frac{1}{2}$

Hope it helps and have a great day! =D

~sunshine~

7 0

3 years ago

Read 2 more answers

I need help with finding the equilibrium prices for each one in the table below. I can't seem to understand how to do it. Please

Neporo4naja [7]

Answer:

it might be $0.85 19 i think not 100% sure plz doint report me

Step-by-step explanation:

3 0

3 years ago

Which operation is used for the equation down below

mario62 [17]

Answer:

B

Step-by-step explanation:

2x+8=9

you want to isolate the variable so you subract 8 from both sides

2x=1

now you want x by itself so you divide by 2 on both sides

x=1/2 or x=0.5

Hope this helped :)

3 0

4 years ago

Prove Forall x elementof Z, x^2 - 5x - 1 is odd.

Diano4ka-milaya [45]

Answer with Step-by-step explanation:

Let Z be a set of integers

We have to prove that $x^2-5x-1$ is odd for all value of x $\in$ Z.

There are two cases

1.When x is an odd integer number

2.when x is even integer number

1.When x is an odd integer number

When x is positive odd integer

Then $x^2$ is positive odd number (because square of odd positive number is always positive an odd number )

5x is also odd number

-5x -1 = -even number

Suppose x=3

Then -15-1=-16

Odd number - even number=Odd number

Hence , $x^2-5x-1$ is an odd number .

When x is negative odd number

Then x square is positive odd number and 5x is negative odd term term

Therefore,odd number + odd number -1=Even number -1=Odd number

Hence $x^2-5x-1$ is an odd number.

2.When x is an even number

When x is positive even number

x square is positive even number and 5x is positive even number

Even number -Even number -1 =Even number -odd number =Odd number

Suppose x=4

$x^2-5x-1$ =16-20-1=-5=Odd number

When x is negative even number

Then x square is positive even number and 5x is negative even number

$x^2-5x-1$ =Even number +Even number -1=Even number -1=Odd number

Hence, for all elements of Z $x^2-5x-1$ is odd.

7 0

3 years ago

Pleaseee help I’m failing I just need one more answer