Solve for q: (4q-6n)/(3m)=f
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Lee sold 60 magazine
Step-by-step explanation:
Terrence and Lee were selling magazines for a charity
- In the first week, Terrance sold 30% more than Lee
- In the second week, Terrance sold 12 magazines, but Lee did not sell any
- Terrance sold 50% more than Lee by the end of the second week
We need to find how many magazines Lee sold
Assume that Lee sold x magazines
∵ Terrance sold 30% more than Lee in the first week
∵ Lee sold x magazines in the first week
- Find 30% of x and add it to x to find how many magazines
Terrance sold
∵ Terrance sold = 30% × x + x
∴ Terrance sold = × x + x = 0.3 x + x
∴ Terrance sold = 1.3 x magazines in the first week
∵ Terrance sold 12 magazines in the second week
- Add 1.3 x to 12 to find the number of magazines that Terrence
sold in the two weeks
∴ Terrence sold 1.3 x + 12 magazines in the two weeks
∵ Lee did not sell any in the next week
∴ Lee sold x magazines in the two weeks
∵ Terrance sold 50% more than Lee by the end of the 2nd week
- Equate 1.3 x + 12 by the sum of x and 50% of x
∴ 1.3 x + 12 = 50% × x + x
∵ 50% × x = × x = 0.5 x
∴ 1.3 x + 12 = 0.5 x + x
- Add the like terms in the right hand side
∴ 1.3 x + 12 = 1.5 x
- Subtract 1.3 x from both sides
∴ 12 = 0.2 x
- Divide both sides by 0.2
∴ 60 = x
Lee sold 60 magazine
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