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guapka [62]
3 years ago
9

SHOW ALL YOUR WORK. REMEMBER THAT PROGRAM SEGMENTS ARE TO BE WRITTEN IN JAVA. Assume that the classes listed in the Java Quick R

eference have been imported where appropriate. Unless otherwise noted in the question, assume that parameters in method calls are not null and that methods are called only when their preconditions are satisfied. In writing solutions for each question, you may use any of the accessible methods that are listed in classes defined in that question. Writing significant amounts of code that can be replaced by a call to one of these methods will not receive full credit. This question involves a game that is played with multiple spinners. You will write two methods in the SpinnerGame class below. public class SpinnerGame { /** Precondition: min < max * Simulates a spin of a spinner by returning a random integer * between min and max, inclusive. */ public int spin(int min, int max) { /* to be implemented in part (a) */ } /** Simulates one round of the game as described in part (b). */ public void playRound() { /* to be implemented in part (b) */ } } (a) The spin method simulates a spin of a fair spinner. The method returns a random integer between min and max, inclusive. Complete the spin method below by assigning this random integer to result. /** Precondition: min < max * Simulates a spin of a spinner by returning a random integer * between min and max, inclusive. */ public int spin(int min, int max) { int result; return result; }

Computers and Technology
1 answer:
adoni [48]3 years ago
4 0

Answer:

Check the explanation

Explanation:

Player 1 Coin

Player 2 Coin

Player 1

Player 2

Round

Count at

Count at

Player

Player

Coin

Coin

Number

Beginning of

Beginning of

1

2

Outcome

Count at

Count at

Round

Round

Spends

Spends

End of

End of

Round

Round

Off-by-

one,

10 - 1

10

10

2

player 2

10 - 2

+

= 8

1

gains 1

= 10

coin

Same,

10 - 2

2

8

10

2

2

player 2

-

gains 1

6

+

=

1

=

9

coin

Off-by-

two,

6 - 1

+

3

6

9

3

player 1

2

9 - 3

gains 2

=

=

7

6

coins

Same,

4

7

6

2

2

player 2

7 - 2

6 - 2+

gains 1

=

5

=

coin

5

Kindly check the attached image below to see the well arranged table to solve the above question.

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Create a program in c/c++ which accepts user input of a decimal number in the range of 1 -100. Each binary bit of this number wi
kirill115 [55]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

void switch_fun(int input)

{

//array to store binary of input number

   int bin[7];

   // convert the number into binary

   for(int i=0; input>0; i++)

       {

           bin[i]=input%2;

           input= input/2;

       }

   // print the switch number and their status

   cout<<"Switch number:\t 1\t 2\t 3\t 4\t 5\t 6\t 7 \n";

   cout<<"status:      ";

   for(int j=6;j>=0;j--)

   {

   // if bit is 1 print "ON" else print "OFF"

       if(bin[j]==1)

           cout<<"\t ON";

       else

           cout<<"\t OFF";

   }

}

int main()

{

   int n;

   cout<<"enter the number between 1-100 only:");

   // read a number in decimal

   cin>>n

   // validate the input

   while(n<1 ||n>100)

   {

     cout<<"wrong input!! Input must be in between 1-100:"<<endl;

     cout<<"enter the number again :";

     cin>>n;

   }

// call the function with input parameter

  switch_fun(n);

return 0;

}

Explanation:

Read a decimal number from user. If the number is not between 1 to 100 the it will again ask user to enter the number until the input is in between 1-100.Then it will call the fun() with parameter n. First it will convert the decimal to binary array of size 7.Then print the status of switch.If bit is 1 then print "ON" else it will print "OFF".

Output:

enter the number between 1-100 only:-5

wrong input!! Input must be in between 1-100:

enter the number again :125

wrong input!! Input must be in between 1-100:

enter the number again :45

Switch number:   1       2       3       4       5       6       7

Status:          OFF     ON      OFF     ON      ON      OFF     ON

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Define an enumeration type triangleType that has the values scalene, isosceles, equilateral, and noTriangle. Write a function tr
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Answer:

#include <iostream>

using namespace std;

int main()

{

   int side1=0;

   int side2=0;;

   int side3=0;

cout <<"Enter side one measurement";

cin >> side1;

cout <<"Enter side two measurement";

cin >> side2;

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cin >> side3;

if(side1+side2>side3||side1+side3>side2||side2+side3>side1){

if (side1==side2 && side2==side3)

{

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}

else if(side1==side2||side2==side3||side1==side3){

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}

else{

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}

}else{

   cout<<"No triangle";

}

   return 0;

}

Explanation:

The code is written in c++. It takes measurements of each side from users as input and check the types of triangle based on the following formula.

1. Equilateral Triangle

If all sides of a triangle are equal than it's an equilateral triangle.

2. Isosceles Triangle

If any two  sides of a triangle are equal than it's an Isosceles triangle.

3. Scalene Triangle

If all the sides of a triangle are of different length than it's an Scalene triangle.

In a triangle the sum of two sides is greater than third side otherwise it's not a triangle.

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