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2 years ago

9

Brian is riding his bike. He biked a distance of 14 miles at a rate of 14 miles per hour. Rearrange the distance formula, d = rt

, to solve for Brian's time in minutes.

1 answer:

Agata [3.3K]2 years ago

8 0

Answer:

60 minutes.

Step-by-step explanation:

Distance = Rate × Time

14 miles = 14mph × ?

Hence, time = 14 miles ÷ 14 mph = 1 hour

1 hour = 60 minutes.

He rode his bike for 60 minutes.

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A pigeon can fly 84 kilometers per hour. how long does the pigeon take to fly 7 kilometers?

Leviafan [203]

84 kilometers ... 1 hour
7 kilometers ... x hours = ?

If you would like to know how long does the pigeon take to fly 7 kilometers, you can calculate this using the following steps:

84 * x = 1 * 7
84 * x = 7 /84
x = 7/84
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Result: A pigeon can fly 7 kilometers in 1/12 hour.

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2 years ago

Read 2 more answers

X-23 / x^2 -x- 20 - 2/5-x

alexira [117]

By simplifying $x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x$ . This will result in a simplified version of $- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$ .

The Simplifying Algorithm is a wonderful way to simplify complex mathematics problems. It can be used to solve equations, convert fractions to decimals, and perform many other math operations. In this problem, the Simplifying Algorithm will help you reduce $x - \frac{{23}}{{{x^2}}} - x - 20 - \frac{2}{5} - x$

Since two opposites add up to 0, remove them from the expression.

$- \frac{{23}}{{{x^2}}} - \frac{{102}}{5} - x$

Write all numerators above the least common denominator 5x2

$- \frac{{115 + 102{x^2} + 5{x^3}}}{{5{x^2}}}$

Use the commutative property to reorder the terms so that constants on the left

$\frac{{ - 5{x^3} - 115 - 102{x^2}}}{{5{x^2}}}$

Rearrange the terms

$\frac{{ - 5{x^3} - 102{x^2} - 115}}{{5{x^2}}}$

By reording the terms

$- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$

Hence, by simplifying this equation, divide both numerator and denominator. This will result in a simplified version of $- \frac{{5{x^3} + 102{x^2} + 115}}{{5{x^2}}}$ .

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3 years ago

A rectangular flower bed covers an area of 11.76 square feet in the garden. The width of the flower bed is 3.5 feet less than it

Degger [83]

The length and width of the garden will be obtain as follows:
let the length be x ft, the width will be (x+3.5)ft
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