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neonofarm [45]
2 years ago
13

P - 12p + -2p - -19p + -13p = 9

Mathematics
1 answer:
USPshnik [31]2 years ago
6 0

Answer:

p=\frac{9}{7}

Step-by-step explanation:

p - 12p + -2p - -19p + -13p = 9\\p(1-12+(-2)-(-19)+(-13)) = 9\\p(-11-2+19-13)=9\\p(7)=9\\p=\frac{9}{7}

Let's check the answer:

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Angle Addition Crossword
Elena-2011 [213]

Answer:

Step-by-step explanation:

1). m∠AEC = m∠AEB + m∠BEC

                  = 21° + 37°

                  = 58°

2). m∠BED = m∠BEC + m∠CED

                   = 37° + 44°

                   = 81°

3). m∠IKF = m∠IKH + m∠HKG + m∠GKF

                = m∠IKH + m∠HKG + m∠IKH [Since, ∠IKH ≅ ∠GKF]

                = 2∠IKH + m∠HKG

         103° = 2∠IKH + 41°

   2(∠IKH) = 103 - 41

 m(∠IKH) = 31°

4). m∠AED = m∠AEB + m∠BEC + m∠CED

                  = 21° + 37° + 44°

                  = 102°

5). m∠JKG = 108°

    m∠JKG = m∠JKI + m∠IKH + m∠HKG

    108° = m∠JKI + 31° + 41°

    m∠JKI = 108° - 72°

    m∠JKI = 36°

6). m∠HKF = m∠GKF + m∠HKG

                  = m∠IKH + m∠HKG [Since, m∠GKF = m∠IKH]

                  = 31° + 41°

                  = 72°

7). m∠NQO = m∠MQN = 64°

8). m∠JKF = m∠JKI + m∠IKF

                 = 36° + 103°

                  = 139°

8). m∠MQO = 2(m∠NQO)

                    = 2(64)°

                    = 128°

9). m∠LQO = 156°

    m∠LQM = m∠LQO - m∠MQO

                    = 156° - 128°

                    = 28°

10. m∠NQP = m∠NQO + m∠OQP

                   = 64° + m∠LQM [Since ∠OQP ≅ ∠LQM]

                   = 64° + 28°

                   = 92°

5 0
3 years ago
The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed
NNADVOKAT [17]

Correct clear question is;

The null and alternative hypotheses are given. Determine whether the hypothesis test is left-tailed, right-tailed, or two-tailed. What parameter is being tested? H_0: μ = 5 H_1: μ ≠ 5

Is the hypothesis test left-tailed, right tailed, or two tailed? A Left tailed B Right tailed C Two tailed

What parameter is being used? A population proportion B population mean C standard deviation

Answer:

A) C - Two tailed hypothesis

B) B - Population mean

Step-by-step explanation:

We are given the hypotheses to be;. Null Hypothesis; H_0: μ = 5

Alternative hypothesis; H_1: μ ≠ 5

From the alternative hypothesis, we can see that the critical area of distribution of the parameter being tested could either be less than 5 or greater than 5 due to the not equal to sign. This means it could either be left tailed or right tailed. Thus, it is a two tailed hypothesis.

From the hypothesis, we see that the symbol μ is being used.

In statistics, μ is generally used as a symbol to denote population mean.

Thus, parameter being used/tested is population mean

4 0
2 years ago
Find the 4th term if the sequend in which a1 = 2 and a n+1 = -4a n + 2
pshichka [43]
a_n_+_1=-4a_n_+_2

dividing both sides by -4, we get:

a_n_+_2=- \frac{a_n_+_1}{4}

this means, each term is its previous term divided by -4.

now we can construct the sequence as follows:

a_1=2

a_2=- \frac{a_1}{4}= - \frac{2}{4}= -\frac{1}{2}

a_3=- \frac{a_2}{4} =- \frac{ \frac{1}{2} }{4}=- \frac{1}{8}

a_4=- \frac{a_3}{4}=- \frac{ \frac{1}{8} }{4}=- \frac{1}{32}



Answer: the last term is -1/32
3 0
3 years ago
What does 100%, 4/4 ,1.000 have in common
Vadim26 [7]
They all end up being 1
100% = 1
4/4 = 1
1.000 = 1
4 0
3 years ago
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3 years ago
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