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2 years ago

13

P - 12p + -2p - -19p + -13p = 9

1 answer:

USPshnik [31]2 years ago

6 0

Answer:

p=\frac{9}{7}

Step-by-step explanation:

$p - 12p + -2p - -19p + -13p = 9\\p(1-12+(-2)-(-19)+(-13)) = 9\\p(-11-2+19-13)=9\\p(7)=9\\p=\frac{9}{7}$

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Jason wakes up for school at 5:30 in the morning. If school starts at 7:00 am, how long in minutes does he have from the time wh

Naddika [18.5K]

Answer:

90 minutes

Step-by-step explanation:

an hour is 60 minutes+ another 30 minutes= 90

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3 years ago

The length of a rectangle is 10 meters more than the width. If the perimeter is 184 meters, what are the length and the width?

Brilliant_brown [7]

Perimeter = (2 × Length) + (2 × Width)

If the length is dependent on the width (because the length is 10 more than the width), we can say that L = W + 10.

To find the answer to the Peri, we have to find out what the W is first.

184 = 2(W + 10) + 2W
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3 years ago

What is 2 over3 times 1 over2

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Multiply straight across

2*1 = 2
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3 years ago

Suppose that from a standard deck, you draw three cards without replacement. What is the expected number of kings that you will

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2 years ago

Consider the diagram below. which of the following represents the values x,y and z?

Gemiola [76]

Answer:

$x=4\sqrt{6}\ units$

$y=4\sqrt{2}\ units$

$z=4\sqrt{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

step 1

In the right triangle ABD

Applying the Pythagorean Theorem

$x^2=y^2+(12-4)^2$

$x^2=y^2+64$

$y^2=x^2-64$ ----> equation A

step 2

In the right triangle BDC

Applying the Pythagorean Theorem

$z^2=y^2+4^2$

$z^2=y^2+16$

$y^2=z^2-16$ ----> equation B

step 3

In the right triangle ABC

Applying the Pythagorean Theorem

$12^2=x^2+z^2$

$144=x^2+z^2$ ----> equation C

step 4

Equate equation A and equation B

$x^2-64=z^2-16$

$x^2=z^2+48$ -----> equation D

step 5

substitute equation D in equation C

$144=z^2+48+z^2$

solve for z

$2z^2=144-48$

$2z^2=96$

$z^2=48$

$z=\sqrt{48}\ units$

simplify

$z=4\sqrt{3}\ units$

Find the value of x

$x^2=z^2+48$

$x^2=48+48=96$

$x=\sqrt{96}\ units$

$x=4\sqrt{6}\ units$

Find the value of y

$y^2=z^2-16$

$y^2=48-16$

$y^2=32$

$y=\sqrt{32}\ units$

$y=4\sqrt{2}\ units$

3 0

3 years ago