Answer:
3(x-2)(x+5)
Step-by-step explanation:
1. Factor out common term 3
3(x^2 +3x-10)
2. Factor (x^2 +3x-10)
3(x-2)(x+5)
Answer:
x = 0, y = 1
Step-by-step explanation:
2x + 6y = 6 → (1)
x - 3y = - 3 ( add 3y to both sides )
x = 3y - 3 → (2)
substitute x = 3y - 3 into (1)
2(3y - 3) + 6y = 6 ← distribute parenthesis and simplify left side
6y - 6 + 6y = 6
12y - 6 = 6 ( add 6 to both sides )
12y = 12 ( divide both sides by 12 )
y = 1
substitute y = 1 into (2)
x = 3(1) - 3 = 3 - 3 = 0
solution is x = 0 , y = 1
Answer:
(2x-5)(3x-2)
Step-by-step explanation:
1)When factoring quadratic equations in for ax²+bx+c you need to separate the b term in a way that the two addends you separate it by should equal a•c. Just do trial and error. In this case you should get -4 and -15. Your separated equation should be:
6x²-4x-15x+10
2)now factor out a common factor from the first two terms and one from the last two terms you should have:
2x(3x-2)-5(3x-2)
3)finally rewrite this equation into two separate factors and you have your answer.
