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2 years ago

In A XYZ If m2 and XZ = X m2 Z, XY = 13% -21, YZ - 8% -6, 4. Find the value of %.

Mathematics

1 answer:

Yanka [14]2 years ago

5 0

Answer: Use this Website www.mathpapa.com

Step-by-step explanation:

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All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$

In which

$(A \cup B) = a + b + (A \cap B)$

65% were found to be proficient in both reading and mathematics.

This means that $A \cap B = 0.65$

78% were found to be proficient in mathematics

This means that $B = 0.78$

$B = b + (A \cap B)$

$0.78 = b + 0.65$

$b = 0.13$

85% of the students were found to be proficient in reading

This means that $A = 0.85$

$A = a + (A \cap B)$

$0.85 = a + 0.65$

$a = 0.20$

Proficient in at least one:

$(A \cup B) = a + b + (A \cap B) = 0.20 + 0.13 + 0.65 = 0.98$

What is the probability that the student is proficient in neither reading nor mathematics?

$(A \cup B) + C = 1$

$C = 1 - (A \cup B) = 1 - 0.98 = 0.02$

There is a 2% probability that the student is proficient in neither reading nor mathematics.

6 0

2 years ago

How to evaluate the expression

jasenka [17]

Answer:

Step-by-step explanation:

$4^{5}$ can be expressed as $2^{(2)(5)}$ = $2^{10}$

Similarly $4^{8}$ can be expressed as $2^{(2)(8)}$ = $2^{16}$

Numerator becomes:

$2^{10}$ · $-2^{9}$ = $-2^{19}$

Denominator becomes:

$2^{16}$ · $-2^{3}$ = $-2^{19}$

Since numerator = Denominator,

Answer = 1

Edit reason: typo

4 0

2 years ago

Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total

dimulka [17.4K]

You can set up a system of equations for this problem. x= number of coach tickets and y = number of first class tickets.

$210x + $1200y = $10,230 (cost of coach ticket plus cost of first class tickets is total budget)

x + y = 11 (number of coach tickets plus number of first class tickets is total number of people)

Solve the second equation for y to get y = 11 - x, then plug that into the first equation and solve for x:

$210x + $1200(11 - x) = $10,230

$210x + $13,200 - $1200x = $10,230

-$990x + $13,200 = $10,230

-$990x = $2,970

x = 3

Sarah bought x = 3 coach tickets. Plug that into the second equation and solve for y:

3 + y = 11

y = 8

Sarah bought y = 8 first class tickets.

6 0

3 years ago

Expand and simplify 5(2x-1) -2(3x+2) First person to answer gets brainliest !!

BlackZzzverrR [31]

Expanded: 4x-9
Simplified: 4x-9

8 0

3 years ago

Read 2 more answers

If carbon monoxide reaches a temperature of over 1,100 degrees Fahrenheit, it will ignite in a combustion reaction with oxygen.

fiasKO [112]

Answer:

A. 2CO + O2 ---> 2CO2