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Ne4ueva [31]
3 years ago
5

I have two bags. Bag 1 contains 10 blue marbles, while Bag 2 contains 15 blue marbles. I pick one of the bags at random, and thr

ow 6 red marbles in it. Then I shake the bag and choose 5 marbles (without replacement) at random from the bag. If there are exactly 2 red marbles among the 5 chosen marbles, what is the probability that I have chosen Bag 1?
Mathematics
1 answer:
Bond [772]3 years ago
6 0

Answer:

The probability of choosing bag 1 is 0,0412

Step-by-step explanation:

As the question emphasizes the probability of bag one, it is that we consider only this one. Bag 1 contains 10 blue marbles and 6 red marbles are added, in total 16 marbles. From this bag 1 extract 3 blue and 2 red marbles, without repetition. In probability it is expressed:

P (Bag₁) = 10/16 * * 9/15 * 8/14 * 6/13 * 5/12 = 0,0412

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tina baked 955 cookies for a big super bowl party she had to put the cookies on 8 different tables in the party room if she spit
sveta [45]

Answer:

119 cookies on each plate and 3 cookies leftover

Step-by-step explanation:

Cookies on each plate:

955 divided by 8 is 119.375 but round it to 119.

Cookies leftover:

Do 119x8 and you will get 952. Then, minus 952 from 955 and your answer is 3 cookies.

i really hope this helps! :)

8 0
3 years ago
Solve the inequalities by graphing. Select the correct graph.<br><br> 5 x + 2 y 3 <br> y x
mrs_skeptik [129]

Answer:

real quick what is the graph for the awnsers sorry but we cant help unless their is a graph

Step-by-step explanation:

4 0
3 years ago
XLiV represents 64 true ya false​
V125BC [204]

Answer:

False

Step-by-step explanation:

Given

XLIV = 64

Required

True or False

The above numeral can be split as follows:

XLIV = XL + IV

X means 10 and L means 50.

But because X (10) which is smaller comes before L (50), XL is executed as:

XL = -10 + 50

XL = 40

In Roman numerals;

IV = 4

Substitute 40 for XL and 4 for IV.

XLIV = 40 + 4

XLIV = 44

Hence;

<em />XLIV = 64<em> is false</em>

7 0
3 years ago
Given the rule, find the 8th term in the arithmetic<br> sequence.<br> an =3n + 4
dybincka [34]

Answer:

You simply substitute 8 for n

A₈ =3(8)+4=28

4 0
3 years ago
Write 5(1.25)^-x standard form with steps
gizmo_the_mogwai [7]

Answer:

Ste4

×

y

=

4

×

(

1

4

x

−

5

)

4

y

=

(

4

×

1

4

x

)

−

(

4

×

5

)

4

y

=

(

4

×

1

4

x

)

−

20

4

y

=

1

x

−

20

Next step is to move the  

x

term to the left side of the equation by subtracting  

1

x

from each side of the equation:

−

1

x

+

4

y

=

−

1

x

+

1

x

−

20

−

1

x

+

4

y

=

−

0

−

20

−

1

x

+

4

y

=

−

20

Now, to make the coefficient of  

x

positive we need to multiply both sides of the equation by  

−

1

−

1

×

(

−

1

x

+

4

y

)

=

−

1

×

−

20

(

−

1

×

−

1

x

)

+

(

(

−

1

×

4

y

)

=

20

1

x

−

4

y

=

20

or

1

x

−

4

y

=

20p-by-step explanation:

4 0
3 years ago
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