Answer:
Step-by-step explanation:
Given is the hexagonal pyramid.
We know the radius of the base is same as its side.
<u>Find the base area:</u>
- A = 3√3/2a²
- A = 3√3/2*6² = 54√3
<u>Given the height and radius, find the side of the lateral triangular faces:</u>
Each of 6 triangles have sides 10, 10 and 6 units.
<u>Find the area using heron's formula:</u>
- s = P/2 = (10*2 + 6)/2 = 13
- s - a = s - b = 13 - 10 = 3
- s - c = 13 - 6 = 7
![A = \sqrt{s(s-a)(s-b)(s-c)} =\sqrt{13*3*3*7} =3\sqrt{91}](https://tex.z-dn.net/?f=A%20%3D%20%5Csqrt%7Bs%28s-a%29%28s-b%29%28s-c%29%7D%20%3D%5Csqrt%7B13%2A3%2A3%2A7%7D%20%3D3%5Csqrt%7B91%7D)
<u>Total surface area:</u>
Correct choice is B
We see from the attached, that kite area = product of the diagonals / 2
The diagonals could be 12 by 8 or
6 by 16 or
3 by 32, etc
It cannot be narrowed down any further.
Answer:
98
Step-by-step explanation:
56 x 1 3/4
56 x 1.75 = 98