The triangles shown below must be congruent. A. True B. False

neonofarm [45]

Answer:

Tim will get £ 8

Sam will get £ 32

Solution,

let the ratios be x and 4x

 $x + 4x = 40 \\ or \: 5x = 40 \\ or \: x = \frac{40}{5} \\ x = 8 \\ replacing \: value \\ 4x \\ = 4 \times x \\ = 4 \times 8 \\ = 32$ 

hope this helps...

Good luck on your assignment...

8 0

2 years ago

Read 2 more answers

Find the value: cos -1 ( - √3/2 )

Natasha2012 [34]

Answer:

The value is undefined.

7 0

3 years ago

Alex used 75% of his savings to buy a mountain bicycle. If the bicycle cost $150, how much money did Alex have saved?

dolphi86 [110]

Alex had 200 dollars saved.

7 0

2 years ago

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What are the ordered pairs of the solutions for this system of equations? f(x) = x^2 – 2x + 3; f (x) = -2x + 19

Naya [18.7K]

Answer:

You can look up math ordered pairs helper and it will help u out If it doesn't work sorry I tried

6 0

3 years ago

Callaway is thinking about entering the golf ball market. The company will make a profit if its market share is more than 20%. A

Vedmedyk [2.9K]

Answer:

$z=\frac{0.224 -0.2}{\sqrt{\frac{0.2(1-0.2)}{624}}}=1.499$

$p_v =P(Z>1.499)=0.0669$

If we compare the p value obtained and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion is not significantly higher than 0.2 or 20%.

Step-by-step explanation:

How would you make the decision if you were Callaway management? Would you use hypothesis testing?

The best way to test the claim if with a proportion test. The procedure is explained below.

1) Data given and notation

n=624 represent the random sample taken

X=140 represent the golf ball purchasers will buy a Callaway golf ball

$\hat p=\frac{140}{624}=0.224$ estimated proportion of golf ball purchasers will buy a Callaway golf ball

$p_o=0.2$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion is more than 0,2 or 20%:

Null hypothesis: $p\leq 0.2$

Alternative hypothesis: $p > 0.2$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.224 -0.2}{\sqrt{\frac{0.2(1-0.2)}{624}}}=1.499$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level is not provided but let's assume $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a right tailed test the p value would be:

$p_v =P(Z>1.499)=0.0669$

If we compare the p value obtained and the significance level assumed $\alpha=0.05$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion is not significantly higher than 0.2 or 20%.

8 0

3 years ago