Answer:
top one yes, bottom one no
Step-by-step explanation:
Answer:
xisans
Step-by-step explanation:
ty z×ynrkkkdiod
Using conditional probability, it is found that there is a 0.1 = 10% probability that the chosen coin was the fair coin.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Three heads.
- Event B: Fair coin.
The probability associated with 3 heads are:
out of 0.5(fair coin).- 1 out of 0.5(biased).
Hence:

The probability of 3 heads and the fair coin is:

Then, the conditional probability is:

0.1 = 10% probability that the chosen coin was the fair coin.
A similar problem is given at brainly.com/question/14398287
Answer:
Here's what I get
Step-by-step explanation:
CPCTC is an acronym for <u>C</u>orresponding <u>P</u>arts of <u>C</u>ongruent <u>T</u>riangles are <u>C</u>ongruent.
If ΔRST ≅ ΔXYZ then
∠R = ∠X
∠S = ∠Y
∠T = ∠Z
RS = XY
ST = YZ
RT = XZ