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3 years ago

What is the measure of BC?

Mathematics

1 answer:

tiny-mole [99]3 years ago

4 0

The measure of BC is 19 as well

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1) Given the area of a Football field (57,600 sqft), and the dimensions of a

Neporo4naja [7]

Answer:

Option (d).

Step-by-step explanation:

Given that,

The area of a Football field is 57,600 sqft

The dimensions of Basketball court is 84ft x 50ft

We need to find what fraction of the football crowd would fit on the court. Taking ratio of the area of basket ball court to the football court as follows :

$R=\dfrac{84\times 50}{57,600}\\\\R=\dfrac{7}{96}\ =\ 0.0729$

It is less than a tenth. Hence, the correct option is (d).

3 0

3 years ago

ASAP! find the slope of a line that is perpendicular to y=-1/2x+4

aliya0001 [1]

We know that :

Ф Product of the slopes of two lines perpendicular to each other should be equal to -1

Let the slope of the line perpendicular to given line be : M

Given equation of the line : y = -1/2x + 4

This line is in the form : y = mx + c, where m is the slope and c is the y intercept

Comparing with y = mx + c :

we can notice that slope of the given line is -1/2

⇒ M × -1/2 = -1

⇒ M × 1/2 = 1

⇒ M = 2

Answer : Slope of the line perpendicular to given line is 2

8 0

3 years ago

Point B lies on AC between

Alecsey [184]

Answer:

A___B___C

AC = AB+ BC

3x +12 = ( 14) + (3-2x)

3x + 12 = – 2x + 17

3x + 2x = 17 - 12

5x = 5

x=5/5

x = 1

AC = 3x + 12 = 3(1) + 12 = 3 + 12= 15

I hope I helped you^_^

5 0

3 years ago

Graph the System and find the point of intersection. 2 and 3x + y = 8 3

LUCKY_DIMON [66]

Google is always a option.

5 0

3 years ago

What are the central angles of the sectors representing nuclear energy in both the years?( you may round the numbers before find

xeze [42]

Answer:

1995 => 22°

2005 => 36°

Step-by-step explanation:

Central angle of the sector representing nuclear energy in 1995 = percentage of nuclear energy in 1995 ÷ 100 × 360°

Nuclear energy is approximately 6% (rounded to whole number) in 1995.

Central angle = $\frac{6}{100}*360 = \frac{6}{10}*36$

$= \frac{216}{10} = 21.6$

Central angle representing nuclear energy in 1995 ≈ 22° (nearest whole number).

Central angle of the sector representing nuclear energy in 2005 = percentage of nuclear energy in 2005 ÷ 100 × 360°

Nuclear energy is approximately 10% (rounded to whole number) in 1995.

Central angle = $\frac{10}{100}*360 = \frac{1}{1}*36$

$= \frac{36} = 36$

Central angle representing nuclear energy in 2005 = 36°.

7 0

3 years ago