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3 years ago

What is the measure of BC?

Mathematics

1 answer:

tiny-mole [99]3 years ago

4 0

The measure of BC is 19 as well

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How do I solve: 3w/x=6e

lana [24]

The answer is ×=w/2e.thats it

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3 years ago

Need help asap please!!!

Alona [7]

Answer:

-6,-4

Step-by-step explanation:

The coordinates of the point is -2,2 so you subtract 4 and 6. That is -6.-4

Hope this helps plz mark brainliest :D

6 0

2 years ago

Read 2 more answers

There are three children’s in Kadri family.the sum of their ages is 15 the product of their age is 80 how old are each of the ka

sasho [114]

Answer:

8, 5, and 2

Step-by-step explanation:

8+5+2= 15

8 x 5 x 2 = 80

8 0

2 years ago

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

5 0

3 years ago

Find the length of segment EG. Show all the work

svp [43]

Answer:

Hi I love you and I miss you

I don't know the answear sorry

5 0

2 years ago