Discriminant. Discriminant, in mathematics, a parameter of an object or system calculated as an aid to its classification or solution. In the case of a quadratic equation ax2 + bx + c = 0, the discriminant is b2 − 4ac; for a cubic equation x3 + ax2 + bx + c = 0, the discriminant is a2b2 + 18abc − 4b3 − 4a3c − 27c2.
Answers and Step-by-step explanations:
When rounding, you should always look at the placement behind what you are trying to round to. So instead of looking at the hundred's placement, which is 0, we need to look at the ten's placement.
(Important:) When rounding, you should always remember that if a number is 1 - 4 when rounding, it does not round up the the next placement. If a number is 5 - 9, then it gets rounded to the next placement.
<em>Hundred's placement:</em> The 9 in the <u>ten's spot </u>(5,0<u>[9]</u>9.620) is on the 5 - 9 scale, so the hundred's placement rounds up to the next number.
5,100.620
<em>Hundredth's placement:</em> Anytime that the "th" is at the end of a word like "hundred" in rounding, it means to go behind (or to the right of) the decimal point. So, 2 falls into the 1 - 4 scale, so it doesn't get rounded.
5,099.600 (or 5,100.600 because of the answer earlier.)
I hope this helps.
Answer:
Step-by-step explanation:
y = 3 - xy
Let x = 1
y = 3 - (1)y
Expand brackets.
y = 3 - y
Add y to both sides.
2y = 3
Divide both sides by 2.
y = 3/2
Answer:
D: {9, 21, 33}
Step-by-step explanation:
Ken worked 2, 8 and 14 hours on 3 separate days.
For working 2 hours, his earnings were f(2) = 2(2) + 5, or 9;
For working 8 hours, his earnings were f(28) = 2(8) + 5, or 21; and
For working 14 hours, his earnings were f(14) = 2(14) + 5, or 33
Thus, the range of this function for the days given is {9, 21, 33} (Answer D)
First, expand the bracket
2.1s + 2.8 - 1.1s = 7.9
Next, collect like terms
s + 2.8 = 7.9
Lastly subtract 2.8 from 7.9 to get your answer.
s = 5.1
(Hope this helps! ^^)
