<h2>Answer: (n^3)/(Q-r)=h</h2>
Factor out h and then divide each side by (Q-r) and you get the answer :) I hope this helped
Perhaps I don't understand the question. You only need to choose one pair that adds to 16, any of {1, 15}, {3, 13}, {5, 11}, {7, 9}.
You can choose up to 4 numbers without getting a pair that adds to 16, so if you choose any 5 numbers, at least one pair of them will add to 16.
The range is 141-116 = 25
Using an online calculator I found the standard deviation to be 10.12
The answer is (3,3) point to X move up four times than to the left 2 times
Use the addition and subtraction theorem:
sin (A + B) = sin A + cos B
sin (A - B) = sin A - cos B
From there it's just a matter of simplification.
sin A cos B = 1/2 [ sin (A + B) + sin (A - B) ]
sin A cos B = 1/2 [ sin A cos B + cos A sin B + sin (A - B) ]
sin A cos B = 1/2 [ sin A cos B + cos A sin B + sin A cos B - cos A sin B ]
sin A cos B = 1/2 [ 2 sin A cos B ]
sin A cos B = sin A cos B
