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Verdich [7]
3 years ago
13

Jane and Philip working together can do a piece of work in 6 days. Jane working alone takes 5 days longer than Philip. How many

days does it take Philip to do the work alone?​
Mathematics
1 answer:
Lapatulllka [165]3 years ago
4 0

Step-by-step explanation:

Jane+Philip= 6 days

Jane = 5 more than P

J= 5+p

(substitute)

5+p+p=6

2p=1

Philip can do the work in 7days.

Jane= 7+5= 12 days

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mary covered her kitchen floor with 10 tiles.The floor measures 6 ft long by 5 ft wide.the tiles are each 3 ft long and w ft wid
Vadim26 [7]
W=(10/(6/3))/5=(10/(2))/5=(5)/5=1

w=1 foot
8 0
3 years ago
If f(x)=x+8 and g(x)=-4-3 find (f+g)(x)
Lilit [14]

Answer:

(f+g)(x) = -3x+5

Step-by-step explanation:

f(x)=x+8 and g(x)=-4x-3

(f+g)(x) = f(x) + g(x)

             = x+8+-4x-3

             = -3x+5

3 0
3 years ago
I only need #22 please help I will give brainliest to 1 of 2 people
PSYCHO15rus [73]

Answer:

all work is shown and pictured

8 0
3 years ago
A contractor is considering a sale that promises a profit of ​$35 comma 000 with a probability of 0.7 or a loss​ (due to bad​ we
Nady [450]

Answer:

$19,100

Step-by-step explanation:

The expected profit would be the probability of profit multiplied by the profit and the sum of probability of loss multiiplied by the loss.

So, we can say:

E(p) = P(p)*P + P(L)*L

Where

E(p) is expected profit

P(p) is probabilty of profit (0.7)

P is the profit (35,000)

P(L) is probability of loss (0.3)

L is the loss (-18,000)

Substituting these values, we get:

E(p) = P(p)*P + P(L)*L

E(p) = (0.7)(35,000) + (0.3)(-18,000)

E(p) = 19,100

The expected profit is $19,100

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