Ask question

Ask question

All categories

3 years ago

15

The graph of an absolute value function has a vertex at (–2, 3) and passes through the point (–1, 0). Using transformations of t

he parent function, has the graph been dilated by a scale factor other than 1? Explain.

2 answers:

Law Incorporation [45]3 years ago

5 0

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

Given vertex:

(-2,3) and (-1,0)

finding slope:

$\bold{Formula:}\\\\\bold{m=\frac{y_2-y_1}{x_2-x_1}}$

$y_2=0\\y_1=3\\x_2=-1\\x_1=-2$

$\ M= \frac{0-3}{-2-(-1)}\\\\\ M= \frac{0-3}{-2+1}\\\\\ M= \frac{-3}{-1}\\\\\ M= 3$

According to the slope value, its value is greater than 1 that's why the graph has been dilated.

erastovalidia [21]3 years ago

3 0

Answer:

Yes, the graph has been dilated.

Using the standard form of the equation, substitute in the values: h = –2, k = 3, x = –1, and y = 0.

Solve the equation to get a = –3.

Graphically, the parent function follows the pattern of right 1, up 1. Moving 1 unit to the right from the vertex, you can move down 3 units to get to the point (–1, 0), so it has been horizontally compressed.

Step-by-step explanation:

Step-by-step explanation:

Edg 2020

You might be interested in

a daily newspaper has 10225 subscribers when it began publication. six years old later it has 8200 subscribers what is the avera

seraphim [82]

Answer:

The rate of change in number of subscriber for the six years is 3.62%

Step-by-step explanation:

Given as :

The initial subscriber of newspaper = p = 10225

The subscriber of newspaper after 6 years of publish = P = 8200

The time period = t = 6 years

Let The average yearly rate of change = r%

<u>Now, According to question</u>

The subscriber of newspaper after n years = initial subscriber × $(1-\dfrac{\textrm rate}{100})^{\textrm time}$

Or, P = p × $(1-\dfrac{\textrm r}{100})^{\textrm t}$

Or, 8200 = 10225 × $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, $\dfrac{8200}{10225}$ = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

Or, 0.80195 = $(1-\dfrac{\textrm r}{100})^{\textrm 6}$

<u>Taking power $\dfrac{1}{6}$ both side</u>

So, $(0.80195 )^{\frac{1}{6}}$ = $((1 - \frac{r}{100} )^{6})^{\frac{1}{6}}$

Or, 0.9638 = 1 - $\dfrac{r}{100}$

Or, $\dfrac{r}{100}$ = 1 - 0.9638

Or, $\dfrac{r}{100}$ = 0.0362

Or, r = 0.0362 × 100

i.e r = 3.62

So, The rate of change in subscriber = 3.62%

Hence, The rate of change in number of subscriber for the six years is 3.62% . Answer

4 0

3 years ago

8. The trapezoids are similar. The area of the smaller trapezoid is 131 m2. Find the area of the larger trapezoid to the nearest

kolbaska11 [484]

Answer:

$3,726\ m^{2}$

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x----> corresponding side of the larger trapezoid

y----> corresponding side of the smaller trapezoid

$z=\frac{x}{y}$

we have

$x=64\ m$

$y=12\ m$

substitute

$z=\frac{64}{12}$

step 2

Find the area of the larger trapezoid

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z----> the scale factor

x----> area of the larger trapezoid

y----> area of the smaller trapezoid

$z^{2}=\frac{x}{y}$

we have

$z=\frac{64}{12}$

$y=131\ m^{2}$

substitute

$(\frac{64}{12})^{2}=\frac{x}{131}$

$x=(\frac{4,096}{144})(131)$

$x=3,726\ m^{2}$

5 0

3 years ago

6 tractors take 7 days to collect

Lyrx [107]

Answer:

= 1.75

Step-by-step explanation:

7/6 divided by 6

= 7/36

7/36 = x/9

Cross multiply fractions:

36x = 63

Divide each side by 36:

x = 7/4 or 1.75

3 0

3 years ago

* The nth term of sequence A is 3n − 2 The nth term of sequence B is 10 − 2n Sally says there is only one number that is in both

Nina [5.8K]

Answer:

Sally is not right

Step-by-step explanation:

Given the two sequences which have their respective $n^{th}$ terms as following:

Sequence A. $3n - 2$

Sequence B. $10 - 2n$

As per Sally, there exists only one number which is in both the sequences.

To find:

Whether Sally is correct or not.

Solution:

For Sally to be correct, we need to put the $n^{th}$ terms of the respective sequences as equal and let us verify that.

$3n-2=10-2n\\\Rightarrow 3n+2n=10+2\\\Rightarrow 5n=12\\\Rightarrow n = \dfrac{12}{5}$

When we talk about $n^{th}$ terms, $n$ here is a whole number not a fractional number.

But as per the statement as stated by Sally $n$ is a fractional number, only then the two sequences can have a number which is in the both sequences.

Therefore, no number can be in both the sequences A and B.

Hence, Sally is not right.

7 0

2 years ago

Elliot has a total of 26 books. He has 12 more fiction books than nonfiction books. Let x represent the number of fiction books

AlladinOne [14]

<u>Answers</u>

19 fiction books

7 nonfiction books

<u>Explanation</u>

x + y = 26 ............................................. (i)

x – y = 12 ............................................ (ii)

Elliot added the two equations and the result was

2x = 38.

Dividing both sides by 2;

x = 19

There are 19 fiction books.

Substituting x in equation (i),

x + y = 26 when x = 19

19 + y = 26

y = 26 - 19

= 7

There are 7 nonfiction books

4 0

3 years ago

Read 2 more answers