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Rashid [163]
3 years ago
10

Which expressions are equivalent to z0.2?

Mathematics
1 answer:
gayaneshka [121]3 years ago
4 0
A is the answer because you convert the radical.
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Can someone please explain how to do number 23 I have no idea how to do it.
taurus [48]
Ok so first equate all the three equations whether by substituting or by eliminating then choose the one das not the answer
3 0
2 years ago
Help?pleaseeee?someone?anyone?
slamgirl [31]

Answer:

the answer is 96

Step-by-step explanation:

(-10)^{2}- 9(\frac{1}{3} )^{2}-3

100-\frac{9}{9}-3

100-1-3

96

6 0
3 years ago
given examples of relations that have the following properties 1) relexive in some set A and symmetric but not transitive 2) equ
rodikova [14]

Answer: 1) R = {(a, a), (а,b), (b, a), (b, b), (с, с), (b, с), (с, b)}.

It is clearly not transitive since (a, b) ∈ R and (b, c) ∈ R whilst (a, c) ¢ R. On the other hand, it is reflexive since (x, x) ∈ R for all cases of x: x = a, x = b, and x = c. Likewise, it is symmetric since (а, b) ∈ R and (b, а) ∈ R and (b, с) ∈ R and (c, b) ∈ R.

2) Let S=Z and define R = {(x,y) |x and y have the same parity}

i.e., x and y are either both even or both odd.

The parity relation is an equivalence relation.

a. For any x ∈ Z, x has the same parity as itself, so (x,x) ∈ R.

b. If (x,y) ∈ R, x and y have the same parity, so (y,x) ∈ R.

c. If (x.y) ∈ R, and (y,z) ∈ R, then x and z have the same parity as y, so they have the same parity as each other (if y is odd, both x and z are odd; if y is even, both x and z are even), thus (x,z)∈ R.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial but not transitive, so the relation provided in (1) satisfies this condition.

Step-by-step explanation:

1) By definition,

a) R, a relation in a set X, is reflexive if and only if ∀x∈X, xRx ---> xRx.

That is, x works at the same place of x.

b) R is symmetric if and only if ∀x,y ∈ X, xRy ---> yRx

That is if x works at the same place y, then y works at the same place for x.

c) R is transitive if and only if ∀x,y,z ∈ X, xRy∧yRz ---> xRz

That is, if x works at the same place for y and y works at the same place for z, then x works at the same place for z.

2) An equivalence relation on a set S, is a relation on S which is reflexive, symmetric and transitive.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial and not transitive.

QED!

6 0
3 years ago
G(y) = 7 – 3y<br> (a) g(0)<br> (b) g(3)<br> (c) g(s + 2)
natulia [17]
A. 7
b. -2
c. 1-3s

7-3(s+2)
7-3s-6
1-3s
5 0
3 years ago
Can someone please help me? :(
Anit [1.1K]

Answer:

____________________________________

\large{ \tt{ \star \: S \: O \: L \: U \: T \: I \: O \: N : }}

\large{ \boxed{ \tt{♡ \: VOLUME \:  = l \:  \times b  \:  \times h}}}

\longrightarrow \: 4 \frac{1}{3}  \times 3 \frac{1}{3}  \times 4

\longrightarrow \:  \frac{13}{3}  \times  \frac{10}{3}  \times 4

\longrightarrow \:  \frac{540}{9}

\longrightarrow \tt \: 57 \frac{7}{9}  \: ft ^{3}

  • Our final answer is 57 7 / 9 ft^3 .

- HappY LearninG ^_________^

4 0
2 years ago
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