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3 years ago

Im dying, someone help with this problem ;)

Mathematics

2 answers:

Amiraneli [1.4K]3 years ago

4 0

Answer is b

24x2+25x−47=−8ax2−3ax+16x−47
-3 at the end for a
i know my stuff :)

kaheart [24]3 years ago

3 0

24x2+ 25x − 47 divided by ax − 2 is equal to

−8x −3 with remainder −53, it is true that (−8x − 3)(ax − 2) − 53 = 24x2 +25x −47. (This can be seen by multiplying each side of the given equation by
ax − 2). This can be rewritten as −8ax2+ 16x − 3ax = 24x2+ 25x − 47.
Since the coefficients of the x2 -term have to be equal on both sides of the equation,

−8a = 24, or a = −3.

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Explain the meaning of 0 in each situation

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not totally sure what you mean by explain the mean of 0, however

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3 years ago

Read 2 more answers

Use properties to rewrite the given equation. Which equations have the same solution as 3/5x +2/3 + x = 1/2– 1/5x? Check all tha

vodomira [7]

we have

$\frac{3}{5}x+ \frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x$

Combine like terms in both sides

$(\frac{3}{5}x+ x)+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

we know that

$(\frac{3}{5}x+ x)=(\frac{3}{5}x+ \frac{5}{5}x)=\frac{8}{5}x$

substitute in the expression above

$\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$ -----> equation A

Multiply equation A by $5*3*2=30$ both sides

$30*(\frac{8}{5}x+\frac{2}{3})=30*(\frac{1}{2}-\frac{1}{5}x)$

$48x+20=15-6x$ ---------> equation B

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$48x+6x=15-20$

$54x=-5$ ---------> equation C

Solve for x

$x=-\frac{5}{54} =-0.09$

We are going to proceed to verify each case to determine the solution.

Case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

the case a) is equal to the equation A

the case a) have the same solution that the given equation

Case b) $18x+20+30x=15-6x$

Combine like terms in left side

$(18x+30x)+20=15-6x$

$(48x)+20=15-6x$

the case b) is equal to the equation B

the case b) have the same solution that the given equation

Case c) $18x+20+x=15-6x$

Combine like terms in left side

$(18x+x)+20=15-6x$

$(19x)+20=15-6x$

$19x+6x=15-20\\25x=-5\\x=-0.20$

$-0.20\neq -0.09$

therefore

the case c) not have the same solution that the given equation

Case d) $24x+30x=-5$

Combine like terms in left side

$54x=-5$

the case d) is equal to the equation C

the case d) have the same solution that the given equation

Case e) $12x+30x=-5$

Combine like terms in left side

$42x=-5$

$x=-5/42=-0.12$

$-0.12\neq -0.09$

therefore

the case e) not have the same solution that the given equation

therefore

the answer is

case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

case b) $18x+20+30x=15-6x$

case d) $24x+30x=-5$

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Nuetrik [128]

6 thousand less than 37,215

6000 less than 37,215 is basically subtracting.

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3 years ago

Please help me with this

timofeeve [1]

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6 * 23/5
138/5 is the answer.

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