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Naily [24]
3 years ago
11

When parallel parking, you should select a space that is __________ as long as your car.

Computers and Technology
1 answer:
Shtirlitz [24]3 years ago
7 0

that is Equally as long as your car


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if a hacker wants to exploit the TCP three-way handshake, what is the most effective way to go about it?
goldfiish [28.3K]

The most effective way to exploit TCP three-way handshake is TCP SYN flood.

  • SYN flood attack is simply a kind of computer attack that begins with 3-way TCP handshake.
  • TCP SYN flood is also called SYN flood and it is a type of distributed Denial of Service (DDoS) attack that uses every part of the normal TCP three-way handshake to eat up resources on the known server and render it non-functional
  • With TCP SYN flood, a hacker can eat up resources of target's computer and makes it unresponsive.

From the above, we can therefore say that the most effective way to exploit TCP three-way handshake is TCP SYN flood.

Learn more from:

brainly.com/question/14739766

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2 years ago
What is the best way to improve an online search
Slav-nsk [51]
Best way is to put your exact question! And do "advanced search"

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3 years ago
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What is the depth of the following tree?
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4 0
2 years ago
Determine the number of character comparisons made by the brute-force algorithm in searching for the pattern GANDHI in the text
leonid [27]

Answer:

Total number of character comparison = 43

Explanation:

Using the Brute force algorithm

The string of n characters is known as text, and the string of m characters is known as the pattern.

From the given information:

The text (n)=THERE_IS_MORE_TO_LIFE_THAN_INCREASING_ITS_SPEED

The pattern (m) = GANDHI

The total no of characters that we have in the text = 47

The total number of characters in pattern = 6

For a brute force algorithm;

Since; the first character of the pattern does not exist in the text, then the number of trials made can be attempted can be expressed as = n – m + 1

= 47 – 6 + 1

= 47 – 5

= 42

Thus; the algorithm will attempt the trial 42 times.

Now, for loop in the algorithm to run 42 times, the G in the pattern will have to align against the for T in the text, and in the last case, it will be aligned against the last space.

On each attempted trial, the algorithm will make one unsuccessful comparison.

However, at the trial at which the G in the pattern Is aligned with the G in the text, there will be two successful comparisons.

Hence, we can calculate the total number of character comparison as follows:

Total number of character comparison = \mathbf{\bigg ( ( 42 -  (no. \ of \  failed \ comparison) ) \times 1 + (1 \times ( Two \ successful \  comparisons) ) \bigg ) }

Total number of character comparison = ( (( 42 – 1) × 1 ) + ( 1 × 2) )

Total number of character comparison = 41 + 2

Total number of character comparison = 43

3 0
3 years ago
Please help me with these short questions >..
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Answer:

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Explanation:

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