Question

Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question.

Answer 1

Answer:

(a) Mean = 42.64

(b) Median= 37

(d)Midrange =39

Step-by-step explanation:

Given data,

60,31,19,55,21,37,94,62,41,15,34

(a)

Mean: Mean is the ratio of all observation to the total number of observation.

$Mean=\frac{\textrn{sum of all observation}}{\textrm{Total number of observation}}$

         $=\frac{60+31+19+55+21+37+94+62+41+15+34}{11}$

        =42.64

(b)

To find the mean of given data,first we have to arrange the date in ascending order or descending order.

Median: Median is middle term of the observation.

15,19,21,31,34,37,41,55,60,62,94

$Median =(\frac{n+1}{2})^{th} term$     n = Total number of observation=11

              $=(\frac{11+1}{2})^{th}term$

              = 6th term

              =37

(c)

Mode is a observation which repeat maximum time.

Here all observations have only one one frequency, so it is multimodel data.

(d)

Midrange: The substraction of first quartile from third quartile.

First quartile: The mid-value of lower half.

Lower portion :15,19,21,31,34

$Q_1=21$

Third quartile: The middle value of upper half.

upper half: 41,55,60,62,94

$Q_3= 60$

Mid range = $Q_3-Q_1$

                 =60-21

                 =39