PLEASE HELP!! URGENT!! the equation of a circle is (x-2)^2 + (y-6)^2=64. What is the center and radius of the circle?
1 answer:
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Answer:
C = $2.40
n = 6
Step-by-step explanation:
For Noelle,
Equation that represents the monthly cost 'C',
C = 0.2n + 1.20
Here, n = number of checks written in a month
For Micah,
Monthly cost for writing checks 'C' = $1.20
Number of checks 'n' = 3
Since, Cost of writing checks ∝ Number of checks written
C' ∝ n
C' = kn
k =
Here, k = proportionality constant
For C' = 1.2 and n = 3
k =
k = 0.4
Equation will be,
C' = 0.4n
For any month C = C'
Therefore, 0.2n + 1.20 = 0.4n
0.4n - 0.2n = 1.20
0.2n = 1.20
n = 6
Number of checks written by Noelle and Micah = 6
For n = 6,
C = 0.2(6) + 1.20
C = $2.40
Cost of writing checks = $2.40
Answer:
Answer:
i) D: All real numbers
ii) R:
iii) Y-int: b=2
Step-by-step explanation:
i) The given absolute value function is
The domain is all values of x that makes the function defined.
The absolute value function is defined for all values of x.
The domain is all real numbers.
ii) The given function is
The function has vertex .
The function is reflected in the x-axis.
This means the vertex is the maximum point on the graph of the function.
The maximum y-value is 5.
The range is therefore or
iii) To find the y-intercept, put into the function.
The y-intercept is (0,2) or
See attachment for graph.
Answer:
Bouquets of roses = 20
Bouquets of carnations = 08
Step-by-step explanation:
Let,
x be the bouquets of roses sold
y be the bouquets of carnations sold
According to given statement;
x + y = 28 Eqn 1
16x + 10y = 400 Eqn 2
Multiplying Eqn 1 by 16
16(x+y=28)
16x + 16y = 448 Eqn 3
Subtracting Eqn 2 from Eqn 3
(16x+16y)-(16x+10y) = 448 - 400
16x + 16y - 16x - 10y = 48
6y = 48
Dividing both sides by 6
Putting y=8 in Eqn 1
x + 8 = 28
x = 28 - 8
x= 20
Hence,
Bouquets of roses = 20
Bouquets of carnations = 08