(X^3-7x+4)+(2x+x-10)

Please see attached! Surface area

grandymaker [24]

Surface area is 10 cm

8 0

2 years ago

¿cual es el perimetro total de un paralelogramo obicuo cuya base mide 2∛54x² cm , y cuyo lado oblicuo mide 3∛54x²?

Step2247 [10]

Answer:

$p=10\sqrt[3]{54}x^2$

Step-by-step explanation:

We are given parallelogram

Since, two opposite sides of any parallelogram are always equal

Let's assume first side =a

second side =b

so, we get

$a=2\sqrt[3]{54}x^2$

$b=3\sqrt[3]{54}x^2$

now, we can find perimeter

perimeter=2a+2b

so, we get

$p=2(2\sqrt[3]{54}x^2)+2(3\sqrt[3]{54}x^2)$

we can simplify it

$p=4\sqrt[3]{54}x^2+6\sqrt[3]{54}x^2$

$p=10\sqrt[3]{54}x^2$ ................Answer

6 0

3 years ago

Read 2 more answers

NORMAL DISTRIBUTIONS AID?

kykrilka [37]

Those are the ranges for one tandard deviation below the mean and one standard deviation above the mean, and we know that 68% of the data falls in that range, so the probability that a randomly chosen worker makes that much is 68%

3 0

3 years ago

Rewrite these in increasing order of length:<br> 133 dm. 433 cm, 308 km, 91 mm

Oksi-84 [34.3K]

$\boxed{91mm$

<h2>Explanation:</h2>

First of all, let's transform each measurement into meter knowing the following relationships:

$1dm=0.1m \\ \\ 1cm=0.01m \\ \\ 1km=1000 m \\ \\ 1mm=0.001m$

Therefore, we can compute the following:

$\bullet \ 133dm \rightarrow 133dm(\frac{0.1m}{1dm})=13.3m \\ \\ \bullet \ 433cm \rightarrow 433cm(\frac{0.01m}{1cm})=4.33m \\ \\ \bullet \ 308km \rightarrow 308km(\frac{1000m}{1km})=308,000m \\ \\ \bullet \ 91mm \rightarrow 91mm(\frac{0.001m}{1mm})=0.091m$