Answer: 69/15=4 and remainder 9
Step-by-step explanation: Since 15 x 4 = 60, 15 can't go into 9 so 9 in the leftover
Answer: 21y^5-28y^4+49y^3
If the remainder isn't necessarily zero, we add C_1y^2+C_2y+C_3, which covers all possible remainders when dividing by a polynomial with leading term in y^3.
Step-by-step explanation:
(3y^2-4y+7)(7y^3) =
21y^5-28y^4+49y^3
Answer: C. The set is not a subspace of set of prime numbers P 9. The set does not contain the zero vector of set of prime numbers P 9.
Step-by-step explanation:
Answer:
-1/2 = x
OR
-0.5 = x
Step-by-step explanation:
1) Isolate x from the equation by making it equal to zero
(Reminder that everything crossing over to the other side of the equation changes it's symbols from positive to negative, and vice-versa is the original symbol was negative)
-7 + 13 + 8x - 2 = 0
-7 + 13 - 2 = -8x
2) Add up common terms on the left side
-9 + 13 = -8x
4 = -8x
3) Divide the entire equation by the number that would leave "x" by itself the factor or number that leaves the number by itself is negative eight since its the number with the equation (-8)
4/-8 = -8x/-8
-1/2 = x
OR
-0.5 = x
Hope this helps :)
Also, if you can is it ok if you can give me brainliest on this?
