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3 years ago

12

The pattern has rows that are 5 tiles wide and an unknown number of rows if you take these tiles and add one additional tile you

can create a pattern that has rows that are 3 tiles wide , with 3more total rows than the original pattern how many rows are in the original pattern

1 answer:

VMariaS [17]3 years ago

6 0

hmm... I'm not sure do you have any more information about the problem?

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A food-packaging apparatus underfills 10% of the containers. Find the probability that for any particular 10 containers the numb

Maksim231197 [3]

Answer:

a) $P(X = 1) = 0.38742$

b) $P(X = 3) = 0.05740$

c) $P(X = 9) = 0.00000$

d) $P(X \geq 5) = 0.00163$

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it is undefilled, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

There are 10 containers, so $n = 10$ .

A food-packaging apparatus underfills 10% of the containers, so $p = 0.1$ .

a) This is P(X = 1)

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

b) This is P(X = 3)

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

c) This is P(X = 9)

$P(X = 9) = C_{10,9}.(0.1)^{9}.(0.9)^{1} = 0.00000$

d) This is $P(X \geq 5)$ .

Either the number is lesser than five, or it is five or larger. The sum of the probabilities of each event is decimal 1. So:

$P(X < 5) + P(X \geq 5) = 1$

$P(X \geq 5) = 1 - P(X < 5)$

In which

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.34868$

$P(X = 1) = C_{10,1}.(0.1)^{1}.(0.9)^{9} = 0.38742$

$P(X = 2) = C_{10,2}.(0.1)^{2}.(0.9)^{8} = 0.1937$

$P(X = 3) = C_{10,3}.(0.1)^{3}.(0.9)^{7} = 0.05740$

$P(X = 4) = C_{10,4}.(0.1)^{1}.(0.9)^{9} = 0.38742$

So

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.34868 + 0.38742 + 0.19371 + 0.05740 + 0.01116 = 0.99837$

Finally

$P(X \geq 5) = 1 - P(X < 5) = 1 - 0.99837 = 0.00163$

3 0

3 years ago

How do I solve this question?

4vir4ik [10]

Answer:

i think it would be 400=10d

5 0

3 years ago

Read 2 more answers

HELP PLS i’ll mark as brainliest if correct

Vlada [557]

Answer:

I believe the answer is the second one

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

You randomly draw a marble from a bag, record its color, and then replace it. You draw a red marble

andre [41]

Make it a fraction
7/25 * 4/4 = 28/100
0.28 = 28 percent

There is a 28 percent chance the next marble will be red

5 0

3 years ago

3a+11=7a-13 with shown work

DaniilM [7]

3a+11=7a-13

move 7a to the other side

sign changes from +7a to -7a

3a-7a+11= 7a-7a-13( combine like terms)

3a-7a+11= -13

-4a+11= -13

move 11 to the other side

sign changes from +11 to -11

-4a+11-11= -13-11

-4a= -13-11

-4a= -24

divide both sides by -4 to get a by itself

-4a/-4= -24/-4

Answer: a= 6

4 0

4 years ago