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kramer
3 years ago
9

What value of x will make the equation true? (√5) (√5)=x​

Mathematics
1 answer:
Marta_Voda [28]3 years ago
8 0

Answer:

25

Step-by-step explanation:

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A chemistry professor who teaches a large lecture class surveys his students who attend his class about how he can make the clas
Iteru [2.4K]

Answer:

a.

Step-by-step explanation:

I believe it's Voluntary Response Bias

7 0
3 years ago
What is the answer to 3k-1=7k+2
Phoenix [80]
Answer is given above

5 0
3 years ago
Read 2 more answers
Hurrrryyyyy plllzzz. Determine the equation of the line that passes through the given points
pashok25 [27]
<h2>Answer:</h2>

y = 2

<h2>Step-by-step explanation:</h2>

To determine the equation of the line that passes through (10,2) and (-3,2), we need to determine the slope of the line. Then substitute the slope and any given point in point slope form to obtain the equation of the line.

<h3>Finding the Slope of the line:</h3>

\implies \text{Slope} = \dfrac{\text{Rise}}{\text{Run}} = \dfrac{y_{2} - y_{1} }{x_{2} - x_{1}  }

\implies \text{Slope} = \dfrac{y_{2} - y_{1} }{x_{2} - x_{1}  }

<u>Substitute the coordinates of the given points:</u>

\implies \text{Slope} = \dfrac{2 - 2}{-3 - 10  }

<u>Simplify the equation to determine the slope:</u>

\implies \text{Slope} = \dfrac{0}{-3 - 10  }

∴ 0 divided by ANY number is ALWAYS 0.

\implies \text{Slope} =0

<h3>Finding the equation of the line:</h3>

Point slope form formula: y - y₁ = m(x - x₁)

  • x₁ and y₁ are the coordinates of any given point.
  • m is the slope

<u>Substitute the values in the point slope form:</u>

\implies \text{Equation of line:} \ y - y_{1}  = m(x - x_{1} )

\implies \text{Equation of line:} \ y - 2  = 0(x - 10)

<u>Simplify the equation to determine the equation of the line:</u>

∴ Any number multiplied by 0 is 0.

\implies \text{Equation of line:} \ y - 2  = 0

\implies \text{Equation of line:} \ y   = 0 + 2

\implies \text{Equation of line:} \ y   = 2

Thus, the equation of the line is y = 2.

5 0
2 years ago
PLEASE HELP!!!! 20 POINTS!!!!
galben [10]
These are two questions and two answers.

Question 1) Which of the following polar equations is equivalent to the parametric equations below? 

<span> x=t²
y=2t</span>

Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>

Explanation:

1) Polar coordinates ⇒ x = r cosθ and y = r sinθ

2) replace x and y in the parametric equations:

r cosθ = t²
r sinθ = 2t

3) work r sinθ = 2t

r sinθ/2 = t 
(r sinθ / 2)² = t²

4) equal both expressions for t²

r cos θ = (r sin θ / 2 )²

5) simplify

r cos θ = r² (sin θ)² / 4

4 = r (sinθ)² / cos θ

r = 4 cosθ / (sinθ)²

r = 4 cot θ csc θ ↔ which is the option A.


Question 2) Which polar equation is equivalent to the parametric equations below?

<span> x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>

Answer: option B) r = sinθ + 1


Explanation:

1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ

2) replace x and y in the parametric equations:

a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span> b) r sinθ =sin²(θ)+sin(θ)</span>

3) work both equations

a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1]  ⇒ r = sinθ + 1


<span> b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
6 0
2 years ago
Read 2 more answers
X+y=5 3x+3y=10 eliminacion
Dominik [7]



[1] y = -x + 5



3x + 3•(-x +5) = 10

0 = -5 => NO solution
8 0
3 years ago
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