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Alecsey [184]
3 years ago
14

What is the value of In e^4 a.0 b.1 c.2 d.4

Mathematics
1 answer:
Zina [86]3 years ago
7 0
\large\begin{array}{l} \textsf{Computing the value of }\mathsf{\ell n (e^4).}\\\\\\ \textsf{Using logarithg properties:}\\\\ \textsf{(logarith of a power)}\\\\ \mathsf{\ell n(e^4)}\\\\ =\mathsf{4\cdot \ell n\,e}\qquad\quad\textsf{(but }\mathsf{\ell n\,e=1}\textsf{)}\\\\ =\mathsf{4\cdot 1}\\\\ =\mathsf{4}\qquad\checkmark\\\\\\\ \textsf{Correct answer: d. 4.} \end{array}


<span>If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2113397


\large\textsf{I hope it helps.}
</span>

Tags: <em>logarithm value compute power property natural log ln</em>

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Jada walks up to a tank of water that can hold up to 10 gallons.When it is active, a drain empties water from the tank at a cons
worty [1.4K]

Answer:

<em>Part A)</em><em>The amount of water in the tank is changing at </em><em>-2/3 gallons per minute. </em>

<em>Part B) </em><em>it will take </em><em>7.5 minutes</em><em> for the tank to drain completely.</em>

<em>Part C) </em><em>The water tank was completely full </em><em>4.5 minutes</em><em> before Jada arrived.</em>

Step-by-step explanation:

<em>Information fetching:</em>

  • Tank of water can hold up-to 10 gallons.
  • When it is active, a drain empties water from the tank at a constant rate.
  • 7 gallons of water present in the tank when Jade first saw
  • 5 gallons of water left after 3 minutes

<em>Part A) At what rate is the amount of water in the tank changing?</em>

As the gallons were decreased from 7 to 5 in three minutes. It means in three minutes, 2 gallons were decreased.

So, gallons per minute change would be <em>-2/3 gallons per minute. </em>Hence, <em>the amount of water in the tank is changing at </em><em>-2/3 gallons per minute. </em>

<u><em>Note</em></u><u><em>: </em></u><u>negative sign indicates the number of gallons of water are decreasing.</u>

<em>Part B) How many more minutes will it take for the tank to drain completely.</em>

Let 'm' be the number of minutes will it take for the tank to drain completely.

As,

(2/3 gallons per minute) (m minutes) = 5 gallons

So,

    m = 5 (3/2)

      = 15/2

      = 7.5 minutes

<em>So, it will take </em><em>7.5 minutes</em><em> for the tank to drain completely.</em>

<em>Part C) How many minutes before Jada arrived was the water tank completely full</em>

As tank of water can hold up to 10 gallons. So, the tank of water is full when there is 10 gallons of water. So, this is 3 gallons of water more than the total 7 number of gallons at the time when Jada arrived.

As Jada arrived when the tank had left 7 gallons.

Let 'm' be the number of minutes before Jada arrived when the water tank was completely full.

So,

    (2/3) (m) = 3

    m = 3(3/2) = 9/2

        = 4.5 minutes

<em>So, the water tank was completely full </em><em>4.5 minutes</em><em> before Jada arrived.</em>

<em />

<em>Keywords: time rate of change, time</em>

<em> Learn more about time rate of change from brainly.com/question/6279456</em>

<em> #LearnwithBrainly </em>

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Write 1/5 as a percent.
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Answer:

0.2

Step-by-step explanation:

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