They only have 1 common point
We find the area of the total square which is 8in • 8in=64in^2 . Now we find the area of the small quadrilateral which is 4in•4in=16 in^2.
Now we subtract the area of the small quadrilateral from the big quadrilateral’s area 64in^2 -16in^2 leaving us with the are of 48in^2 of the figure
Answer: 1. muiltply the two volumes 2. 273.32 cubic centimeters are your answers hopefully I'm correct on this.
