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lorasvet [3.4K]

3 years ago

10

If a pair of two idenrcal dice are rolled n successive rmes, how many sequences of outcomes contain all six doubles (i.e., two 1

's, two 2's, ... ,two 6's)?

1 answer:

schepotkina [342]3 years ago

8 0

I think the answer is six

(1,1) , (2,2) , (3,3) , (4,4) , (5,5) , (6,6)

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A football team was training for four hours. During the first hour, they practiced for 5/8 of an hour. During the second hour, t

Leviafan [203]

Answer: 2 19/24 hours was spent in practising.

Step-by-step explanation:

During the first hour, they practiced for 5/8 of an hour. During the second hour, they practiced for 2/3 of an hour. This means that the total time for which they practiced in the first 2 hours would be

5/8 + 2/3 = 31/24 hours

During the last two hours, they first practiced for 3/5 of an hour, took a 1/2 hour break and then practiced the rest of the time. This means that the rest of the time for which they practiced is

2 - (3/5 + 1/2) = 2 - 11/10 = 9/10

Therefore, the time they spent practicing in total would be

31/24 + 3/5 + 9/10 = 67/24 =

2 19/24 hours

7 0

3 years ago

What is five ninths plus four sixths

Minchanka [31]

Answer: 1.22222222222

Step-by-step explanation:

3 0

3 years ago

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Savannah planned to evenly disperse 400 chocolate chips among the x pans of brownies. Unfortunately, the last pan of brownies re

bonufazy [111]

400 - 32 which equals 368

4 0

3 years ago

Please help me In this

aniked [119]

Answer:

I think its C i think might be wrong

8 0

3 years ago

Is 7/8 or 11/10 closer to 1? How did you decide anybody help please?

erik [133]

Let

A-----> $\frac{7}{8}$

B-----> $\frac{11}{10}$

C-----> $1$

we know that

Point A-------> Multiply numerator and denominator by $10$

$\frac{7*10}{8*10} =\frac{70}{80}$

Point B-------> Multiply numerator and denominator by $8$

$\frac{11*8}{10*8} =\frac{88}{80}$

Point C-------> Multiply numerator and denominator by $80$

$\frac{1*80}{1*80} =\frac{80}{80}$

Find the distance Point A to Point C

$\frac{80}{80} -\frac{70}{80} =\frac{10}{80}$

Find the distance Point B to Point C

$\frac{88}{80} -\frac{80}{80} =\frac{8}{80}$

therefore

$\frac{8}{80} < \frac{10}{80}$

Point B is closer to Point C

$\frac{11}{10}$ is closer to $1$

the answer is

$\frac{11}{10}$ is closer to $1$

5 0

3 years ago

Read 2 more answers