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3 years ago

PLEASE HELP!

Mathematics

1 answer:

Leona [35]3 years ago

7 0

Answer:

The initial temperature of the object was 37.6

Step-by-step explanation:

we have

$f(t)=Ce^{(-kt)} +20$

where

f(t) represent the temperature of the object in degree Celsius

t is the time in minutes

Find the value of the constant C

we have the ordered pair (4,35)

substitute in the equation and solve for C

$35=Ce^{(-0.0399*4)} +20\\Ce^{(-0.0399*4)}=15\\C=15/e^{(-0.0399*4)}\\C=17.6$

Find the initial value of the object

we know that

The initial temperature is the value of f(t) when the value of t is equal to zero

For t=0

$f(0)=(17.6)e^{(-k*0)} +20\\f(0)=17.6 +20\\f(0)=37.6$

therefore

The initial temperature of the object was 37.6 (I not include units)

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3 years ago

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3 years ago

You must show your staterment and reason T-chart to get full credit

marissa [1.9K]

Step-by-step explanation:

RS bisects PQ at T. PQ bisects RS at T.

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<h3>Statements..............................Reasons</h3>

(1) RS bisects PQ at T.................(1) Given

(2) PQ bisects RS at T.................(2) Given

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5 0

3 years ago

What is the distance between the following coordinates? Show work.

miss Akunina [59]

Answer:

$\huge{ \boxed{ \bold{ \tt{2 \sqrt{26}}} \: \: \text{units} } }$

<h3>♁ Question :</h3>

Find the distance between ( 5 , -6 ) and ( 3 ,4 ).

<h3>♁ Step by step explanation:</h3>

Let the points be A and B. Now,

Let, A ( 5 , -6 ) ⇢ ( x₁ , y₁ )
Let, B ( 3 , 4 ) ⇢ ( x₂ , y₂ )

Use the distance formula to determine the distance between A ( 5 , -6 ) and B ( 3 , 4 ).

$\boxed{ \underline{ \sf{distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}}$

Substitute the actual value of the points into the distance formula and then simplify.

$\dashrightarrow{ \sf{ \sqrt{ {(3 - 5)}^{2} + {(4 - ( - 6))}^{2} } }}$

Remember : The positive and negative integer are always subtracted but posses the sign of the bigger integer.

$\dashrightarrow{ \sf{ \sqrt{ {( - 2)}^{2} + {(4 - ( - 6))}^{2} } }}$

Remember : ( - ) × ( - ) = ( + )

$\dashrightarrow{ \sf{ \sqrt{ {( - 2)}^{2} + {(4 + 6)}^{2} } }}$

Add the numbers : 4 and 6

$\longrightarrow{ \sf{ \sqrt{ {( - 2)}^{2} + {(10)}^{2} } }}$

Evaluate the power

$\longrightarrow{ \sf{ \sqrt{4 + 100}}}$

Add the numbers : 4 and 100

$\dashrightarrow{ \sf{ \sqrt{104}}}$

$\dashrightarrow{ \boxed{ \sf{2 \sqrt{26} }}}$ units

Therefore , The distance between ( 5 , -6 ) and ( 3 , 4 ) is $\sf{2 \sqrt{26}}$ units .

And we're done!

Hope I helped!

Have a wonderful time ! シ

~TheAnimeGirl

5 0

3 years ago

PLX HELP! Need this ASAP! Thx

Luba_88 [7]

Same side angles together form angle with measure 180^{0}. Let x be a measure of smaller angle, then x+20^{0} is measure of bigger angle.
x+x+20^{0}=180^{0}
2x=160^{0}
x=80^{0}.
So measure of smaller angle is 80^{0} and measure of bigger angle is x+20^{0}=80^{0}+20^{0}=100^{0}.

7 0

3 years ago

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