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o-na [289]
3 years ago
9

On a number line, what is x-4<-3?

Mathematics
1 answer:
goblinko [34]3 years ago
3 0

Add 4 to both sides

x - 4 < -3

x-4+4 < -3+4

x < 1

To graph this on a number line, plot an open circle at 1 on the number line. Do not fill in the open circle. Shade to the left of the open circle. The shaded region represents all x values smaller than 1.

The graph is shown below.

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A customer gives you a $100 bill for a purchase that totals $22.75. What is the best money combination to give the $77.25 to the
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3, 20 bills 60 dollars add 1, 10 bill to get to 70 dollars add 1, 5 bill you get 75 dollars add 2,1 bills to get 77 dollars finaly 1 quarter to get 77 dollars and 25 cents

4 0
3 years ago
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Let ? = {a, b, c} be a sample space. let m(a) = 1/2, m(b) = 1/3, and m(c) = 1/6. find the probabilities for all eight subsets of
Leviafan [203]
<span>
A= {a,b,c} . Since this set has 3 elements, the number
of its total subset is 2³ = 8 (including the Ф element):

Here below all the subsets of {a,b,c}, with their related probabilities, knowing that P(a) = 1/2 ; P(b) = 1/3 and P(c) = 1/6

{a}        </span>→→→→1/2
<span>{b}        </span>→→→→1/3
<span>{c}        </span>→→→→1/6
<span>{a,b}     </span>→→→→1/2 + 1/3 =  5/6
<span>{a,c}     </span>→→→→1/2 + 1/6  =  2/3
<span>{b,c}     </span>→→→→1/3 + 1/6  =  1/2
<span>{a,b,c}  </span>→→→→1/2 + 1/3 + 1/6 = 1
<span>{∅}       </span>→→→→0 =0
5 0
3 years ago
Write an equation in point slope form of the he that passes through the point (2.1) and has a slope of 2
Wewaii [24]

Answer:

y=2x-3

Step-by-step explanation:

show work

1=(2*2)+b

1=4+b

1-4=-3

-3=b

check work

y=2x-3

y=(2*2)-3

y=4-3

y=1

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NikAS [45]

8 is the greatest

Note the sign, and look at it on a number line.

8 is bigger than -3 by 11

hope this helps

4 0
3 years ago
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Use the elimination to solve this equation. <br><br> 2x+3y=55 <br> 9x+4y=105
seropon [69]
X=5 y=15 (5,15). 
This is how you do it:
-4(2x+3y=55): -8x-12y=-220
3(9x+4y=105):27x+12y=315

You add the two new equations together, canceling out the y values, and get the x value. Then, you go back and plug in the x value in the original equation to get the y value.

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