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storchak [24]
3 years ago
12

**only one question** ____ tens = 3700

Mathematics
1 answer:
mestny [16]3 years ago
3 0

Answer:

370 tens = 3700

Step-by-step explanation:

3700/10 = 370

so

370 x 10 = 3700

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One half of a pizza
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The sum of two numbers is 52. The greater number is 4 more than the smaller number. Which equation can be used to solve for the
MA_775_DIABLO [31]

Answer:Let's assume x be the smaller number.

Given that, The greater number is 4 more than the smaller number.

So, greater number= x+4.

It's also given that, The sum of two numbers is 52. Which means sum of x and x+4 must be equa to 52. Hence,

x + (x + 4) = 52

Step-by-step explanation:

6 0
2 years ago
Figure a is dilated by a scale factor of 1/2 to form figure b. What is the length of x?
PIT_PIT [208]

Answer:

The correct option is 3. The value of x is 8 inches.

Step-by-step explanation:

It is given that Figure A is dilated by a scale factor of 1/2 to form Figure B. It means both figure are similar and corresponding sides of similar figures are proportional.

\text{scale factor}=\frac{\text{Side of image}}{\text{Side of preimage}}

\frac{1}{2}=\frac{x}{16}

Multiply both sides by 16.

\frac{16}{2}=x

8=x

Since scale factor is 1/2, so we can directly say that the side length of image is half of the corresponding side of preimage.

The length of x is 8 inches. Therefore the correct option is 3.

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4 years ago
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A box office sold 147,523 tickets for an auto race.
Marysya12 [62]

Answer:

78,799 children's tickets

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147,523 total tickets, 68,724 adult tickets

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5 0
3 years ago
ABCD is a trapezoid.<br> What is the area of trapezoid?
lana [24]
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
  Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
  Area = (1/2)(AB + AB/4)·h = (5/8)AB·h

The given dimensions let us determine the area of ∆BCE to be
  Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²

The total area of the trapezoid is also the sum of the areas ...
  Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
  Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
  Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h

Putting all of the above into the equation for the total area of the trapezoid, we have
  Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
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  AB·h = (30 cm²)/(3/8) = 80 cm²

Then the area of the trapezoid is
  Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
6 0
3 years ago
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