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AlladinOne [14]
3 years ago
8

repps Corporation produces a single product. Last year, Krepps manufactured 25,000 units and sold 20,000 units. Production costs

for the year were as follows: Direct materials 180,000 Direct labor 120,000 Variable manufacturing overhead 210,000 Fixed manufacturing overhead 250,000 Sales totaled $850,000 for the year, variable selling and administrative expenses totaled $110,000, and fixed selling and administrative expenses totaled $170,000. There was no beginning inventory. Assume that direct labor is a variable cost. The contribution margin per unit was:
Business
1 answer:
k0ka [10]3 years ago
4 0

Answer:

unitary contribution margin= $16.6

Explanation:

Giving the following information:

Direct materials 180,000

Direct labor 120,000

Variable manufacturing overhead 210,000

Variable selling and administrative expenses= $110,000

Sales totaled $850,000

<u>First, we need to calculate the unitary production variable cost:</u>

Unitary production variable cost= 510,000/25,000= $20.4

<u>Now, the total unitary variable cost and the selling price:</u>

Total unitary variable cost= (110,000/20,000) + 20.4= $25.9

Selling price= 850,000/20,000= $42.5

<u>Finally, the unitary contribution margin:</u>

unitary contribution margin= 42.5 - 25.9

unitary contribution margin= $16.6

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1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

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So then we satisfy this condition

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

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For this case we have a sample of n =25

And we are interested in the proportion of registered students that spend more than 20 minutes to get to school.

X = 13 represent the number of students in the sample selected that have a time more than 20 min.

And then the estimated proportion of interest would be:

\hat p = \frac{X}{n}= \frac{13}{25}= 0.52

And we want to check if we can use the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

So in order to do this approximation we need to satisfy some conditions listed below:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

n\hat p =25*0.52= 13 \geq 10

n(1-\hat p) = 25*(1-0.52) =12 \geq 10

So then we satisfy this condition:

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})

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a. Yes.

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